Question

我有一个如下所示的family_expenses表：

family_id    bank_code    amount    year   month
  001          LB         130.00    2017     1
  001          MB         200.00    2017     1
  001          CB          78.00    2017     2
  001          SB          69.00    2017     3
  009          LB          78.00    2017     1

上表中还有其他几列。

我需要做的是获取一个家庭ID的所有记录，并将其与另一个表中的另一个子查询相结合。我使用CASE WHEN做了一些查询。
我的查询如下：

 SELECT
(CASE WHEN t.rownum = 1 THEN t.bank_code ELSE '' END
) as bank_code1,
(CASE WHEN t.rownum = 1 THEN t.amount ELSE 0.00 END
) as amt1,
(CASE WHEN t.rownum = 2 THEN t.bank_code ELSE '' END
) as bank_code2,
(CASE WHEN t.rownum = 2 THEN t.amount ELSE 0.00 END
) as amt2,
(CASE WHEN t.rownum = 3 THEN t.bank_code ELSE '' END
) as bank_code3,
(CASE WHEN t.rownum = 3 THEN t.amount ELSE 0.00 END
) as amt3
FROM
(
select  
ROW_NUMBER() OVER(partition by family_id Order by family_id, bank_code) 
as rownum, 
family_id, bank_code, AMOUNT
from family_expenses
where year = 2017 and month = 1
and family_id= 001
) t

结果显示2行记录。

bank_code1     amt1       bank_code2   amt2    bank_code3     amt3
   LB         130.00
                             MB       200.00

如何让输出显示所有列在一行中显示结果？

预期产出：

bank_code1     amt1       bank_code2   amt2    bank_code3     amt3
   LB         130.00         MB       200.00

Answer 1

尝试这样（只需修改原始代码）......

IF OBJECT_ID('tempdb..#family_expenses', 'U') IS NOT NULL 
DROP TABLE #family_expenses;

CREATE TABLE #family_expenses (
    family_id CHAR(3) NOT NULL,
    bank_code CHAR(2) NOT NULL,
    amount MONEY NOT NULL,
    [year] INT NOT NULL,
    [month] TINYINT NOT NULL 
    );
INSERT #family_expenses (family_id, bank_code, amount, [year], [month]) VALUES
    ('001', 'LB', 130.00, 2017, 1),
    ('001', 'MB', 200.00, 2017, 1),
    ('001', 'CB', 78.00, 2017, 2),
    ('001', 'SB', 69.00, 2017, 3),
    ('009', 'LB', 78.00, 2017, 1);

SELECT
    t.family_id,
    bank_code1 = MAX(CASE WHEN t.rownum = 1 THEN t.bank_code END ),
    amt1 = SUM(CASE WHEN t.rownum = 1 THEN t.amount END),
    bank_code2 = MAX(CASE WHEN t.rownum = 2 THEN t.bank_code END ),
    amt2 = SUM(CASE WHEN t.rownum = 2 THEN t.amount END ),
    bank_code3 = MAX(CASE WHEN t.rownum = 3 THEN t.bank_code END ),
    amt3 = SUM(CASE WHEN t.rownum = 3 THEN t.amount ELSE 0.00 END )
FROM
    (   
    SELECT
        rownum = ROW_NUMBER() OVER (PARTITION BY fe.family_id ORDER BY fe.family_id, fe.bank_code ),
        fe.family_id,
        fe.bank_code,
        fe.amount
    FROM
        #family_expenses fe
    WHERE
        fe.year = 2017
        AND fe.month = 1
        AND fe.family_id = '001'
    ) t
GROUP BY
    t.family_id;

结果...

family_id bank_code1 amt1                  bank_code2 amt2                  bank_code3 amt3
--------- ---------- --------------------- ---------- --------------------- ---------- ---------------------------------------
001       LB         130.00                MB         200.00                NULL       0.0000

例如，当rownum（）返回行时

1 个答案: