Question

我在我的应用中使用片段。每个片段都有一个列表视图。 ListView是包含单个图像视图的自定义列表视图。

 <ImageView
    android:id="@+id/imageView3"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_weight="1"
    app:srcCompat="@android:drawable/ic_notification_overlay" />

列表视图项目是图像。我想实现searchview。我想按每个listview项目的名称搜索，例如“jingle bells etc”以及数字，即“1,2 ...等等。

我的包含listview标题的java文件是。

public class carolFrag extends Fragment {

//code

public carolFrag() {
    // Required empty public constructor
}

public void onCreate(Bundle savedInstanceState){
    super.onCreate(savedInstanceState);

}

private static final String TAG = "carolFrag";

@Nullable
@Override
public View onCreateView(LayoutInflater inflater, @Nullable ViewGroup main_content, @Nullable Bundle savedInstanceState) {
    View view = inflater.inflate(R.layout.fragment_carol, main_content, false);


    final int[] menuImage = {R.drawable.carol_1_title, R.drawable.carol_2_title,R.drawable.carol_3_title,R.drawable.carol_4_title,R.drawable.carol_5_title,R.drawable.carol_6_title,R.drawable.carol_7_title,R.drawable.carol_8_title,R.drawable.carol_9_title,R.drawable.carol_10_title,R.drawable.carol_11_title};
    final ListView listView = (ListView) view.findViewById(R.id.CarolList);

    listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> adapterView, View view, int position, long l) {


            Intent intent1 = new Intent (getActivity(), PackageC.class)  
            intent1.putExtra("position", position);
            startActivity(intent1);




        }
    });
    AdapterCarols adapter = new AdapterCarols(getContext(), menuImage);
    listView.setAdapter(adapter);

    // Inflate the layout for this fragment



    return view;
}

}

我无法制作任何逻辑，因为数组中有drawable。

Answer 1

因为阵列中充满了可绘制的数据，并且它不是数据库的东西，也不是每个解决方案，所以我将会得到一个解决方案。我相信，简单的是让另一个数组可能是一个 - String [] - 其中drawable的名称与它们在原始中的顺序相同 - final int [] menuImage - 你可以在String数组中进行搜索并保存结果的位置。然后使用这些位置创建一个新数组（int []），在这个新数组中放入与这些位置匹配的drawable。最后更改列表视图的适配器，传递带有结果的数组和notifydatachange（）;在列表视图中，它可以直观地更新。

public View onCreateView(LayoutInflater inflater, @Nullable ViewGroup 
main_content, @Nullable Bundle savedInstanceState) {
View view = inflater.inflate(R.layout.fragment_carol, main_content, false);


final int[] menuImage = {R.drawable.carol_1_title, R.drawable.carol_2_title,R.drawable.carol_3_title,R.drawable.carol_4_title,R.drawable.carol_5_title,R.drawable.carol_6_title,R.drawable.carol_7_title,R.drawable.carol_8_title,R.drawable.carol_9_title,R.drawable.carol_10_title,R.drawable.carol_11_title};


final ListView listView = (ListView) view.findViewById(R.id.CarolList);

SearchView sv = view.findviewById(R.id.searchview);
 sv.setOnQueryTextListener(new SearchView.OnQueryTextListener()
            {
                public boolean onQueryTextChange(String par1)
                {
                    return false;
                }

                public boolean onQueryTextSubmit(String par1)
                {

                      int [] searchresults = PerformSearch(par1);
                       AdapterCarols newadapter = new 
                               AdapterCarols(getContext(), searchresults);
                       listView.setAdapter(adapter);   
                     listview.invalidate(); // don't remember listview refresh method. I work with Recyclerview, they have a notifyDatasetChange(); method.   

                 }
         });

listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
    @Override
    public void onItemClick(AdapterView<?> adapterView, View view, int position, long l) {


        Intent intent1 = new Intent (getActivity(), PackageC.class)  
        intent1.putExtra("position", position);
        startActivity(intent1);




    }
});
AdapterCarols adapter = new AdapterCarols(getContext(), menuImage);
listView.setAdapter(adapter);

// Inflate the layout for this fragment



return view;
}


private int[] PerformSearch(par1)
{

String [] strcarols = {carol_1_title,carol_2_title,carol_3_title,carol_4_title,carol_5_title,carol_6_title,carol_7_title,carol_8_title,carol_9_title,carol_10_title,carol_11_title};

 int[] menuImage = {R.drawable.carol_1_title, R.drawable.carol_2_title,R.drawable.carol_3_title,R.drawable.carol_4_title,R.drawable.carol_5_title,R.drawable.carol_6_title,R.drawable.carol_7_title,R.drawable.carol_8_title,R.drawable.carol_9_title,R.drawable.carol_10_title,R.drawable.carol_11_title};

int[] results = new int[];

int carolsresultcount = 0, index =0;
   /// simplest way
   for(String carol:strcarols)
   {
     if(carol.contains(par1))
      {
         results [carolsresultcount++] = menuImage [index];
       }
      index++;
   }

return results;


}

我希望这可以解决你的问题。

SearchView里面包含ListView的片段？

1 个答案: