for正在使用JavaScript中的最后一项

Question

我有这段代码

<?php  $json = json_encode($question->varz); ?>

@section('script')
<script type="text/javascript">
const nameSelect = $('<select></select>');
const person1 = $(' @foreach($question->answers as $answer)@if($answer->drop_down_owner==0) <option value="person1"> {{$answer->text}}</option>  @endif @endforeach');
nameSelect.append(person1);
const ageSelect = $('<select></select>');
const age1 = $(' @foreach($question->answers as $answer)@if($answer->drop_down_owner==1) <option value="person1"> {{$answer->text}}</option>  @endif @endforeach');
ageSelect.append(age1);


var json = <?php echo $json; ?>;
const dropdown = [ nameSelect, ageSelect];

 for (var i = 0; i < json.length; i++)
      {
         if(json[i] != "#KDPOPTION"){
            $('#dropdowns').append(json[i]);
         }else
         {
              $('#dropdowns').append($(dropdown[0]));

         }
      }

</script>

，结果为IamandIam[appears the dropdown]yearsold。我需要下拉列表出现在像这样的两个地方

Iam[appears the dropdown]andIam[appears the dropdown]yearsold.

所以，如果我按<4，则下拉列表出现在第一位，如果i <7或更大，则下拉列表仅出现在最后一个位置。