将文件提交到网址后获取响应/结果

时间:2017-08-29 11:44:22

标签: php response

我正在尝试将文件提交到REST API网址,并且需要从此流程获取响应/结果。我正试图将它发送到另一个PHP并显示结果,但没有。如果它可以显示在同一个php页面,那就更好了。我怎么想这样做?

<?php
session_start();
// Start the session
$responseURL = "http://my-site.com/responseform.php";
$url = 'https://api-to-validate-file.com/api/validate';
$header = array('Content-Type: multipart/form-data','Authorization: apikey=0f0f0f0f0f0f0f0f0f0f0f0f0f0f0f');
$fields = array('filename' => '@' . $_FILES['filename']['tmp_name'][0]);
$token = 'NfxoS9oGjA6MiArPtwg4aR3Cp4ygAbNA2uv6Gg4m';

$resource = curl_init();
curl_setopt($resource, CURLOPT_URL, $url);
curl_setopt($resource, CURLOPT_HTTPHEADER, $header);
curl_setopt($resource, CURLOPT_RETURNTRANSFER, true);
curl_setopt($resource, CURLOPT_POST, true);
curl_setopt($resource, CURLOPT_POSTFIELDS, $fields);
curl_setopt($resource, CURLOPT_COOKIE, 'apiToken=' . $token);
$result = json_decode(curl_exec($resource));
///echo 'The body of the response is ' . $result;
curl_close($resource);
?>

<form method="post" action="index.php" enctype="multipart/form-data">
    <input name="filename" type="file" />
    <input type="submit" value="Upload" />
    <input type="hidden" name="RespURL" value="<?= $responseURL ?>"><br>
</form>

0 个答案:

没有答案