Question

当我尝试将我的CreateAPIView添加到router.register时，它会引发TypeError异常：

  File "/home/denys/.virtualenvs/buddha_test/lib/python3.5/site-packages/rest_framework/routers.py", line 281, in get_urls
    view = viewset.as_view(mapping, **route.initkwargs)
TypeError: as_view() takes 1 positional argument but 2 were given

但是如果我直接将url添加到urlpatterns就可以了！结果是我想看到API Root中的链接：

enter image description here

所以我可以写这样的东西：

urls.py

from django.conf.urls import url, include
from . import views
from rest_framework import routers

router = routers.DefaultRouter()
router.register(r'clients-list', views.ClientList)
router.register(r'managers-list', views.ManagerList)
router.register(r'clients', views.CleintCreate, base_name='create')


urlpatterns = [
    url(r'^', include(router.urls)),

]

views.py

from .models import Client, Manager
from .serializers import ClientSerializer, ManagerSerializer
from rest_framework import generics
from rest_framework import viewsets
from rest_framework.permissions import IsAuthenticated, AllowAny
from rest_framework.generics import CreateAPIView
from rest_framework.decorators import detail_route

class ClientList(viewsets.ModelViewSet):

    permission_classes = (IsAuthenticated, )

    queryset = Client.objects.all()
    serializer_class = ClientSerializer


class ManagerList(viewsets.ReadOnlyModelViewSet):

    permission_classes = (IsAuthenticated, )
# 
    queryset = Manager.objects.all()
    serializer_class = ManagerSerializer


class CleintCreate(CreateAPIView):

    model = Client
    serializer_class = ClientSerializer
    permission_classes = (AllowAny,)

Answer 1

您可以创建CreateAPIView并继承GenericViewSet，而不是实施CreateModelMixin：

views.py：

# ...

class ClientCreate(CreateModelMixin, GenericViewSet):
    model = Client
    serializer_class = ClientSerializer
    permission_classes = (AllowAny,)

然后在你的urls.py中，它就是一样的：

from django.conf.urls import url, include

from rest_framework import routers

from . import views


router = routers.DefaultRouter()
router.register(r'clients-list', views.ClientList)
router.register(r'managers-list', views.ManagerList)
router.register(r'clients', views.ClientCreate, base_name='create')


urlpatterns = [
    url(r'^', include(router.urls)),
]

我可以在django rest中使用DefaultRouter和CreateAPIView吗？

1 个答案: