如何创建包含一系列字母数字的列表？

Question

我有这个清单，

['1A11','1A12','1A13','1A14','1A15','1A16','1A17','1A18']

如何使用python创建列表，该列表使用上面的范围并将输出打印为：

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感谢。

Answer 1

def make_range(pre, r):
    return ['{0}{1}'.format(pre, i) for i in r]

# Example
print (make_range('1A1', range(1, 8)))
# Will print
>>> ['1A11','1A12','1A13','1A14','1A15','1A16','1A17','1A18']

Answer 2

简单的列表理解：

l = ['1A11','1A18']
result = [ l[0][:2]+str(i) for i in range(int(l[0][2:]), int(l[1][2:])+1) ]

print(result)

输出：

['1A11', '1A12', '1A13', '1A14', '1A15', '1A16', '1A17', '1A18']