Question

我的表帐户中有一个名为 weight 的列。我需要从这个列中获取值，如

当用户点击40 - 100的重量时，需要显示重量在40到100之间的所有人。

这是我的HTML代码，

<div class="float-right span35">
    <form class="list-wrapper search-form" method="get" action="{{CONFIG_SITE_URL}}/index.php">
        <div class="list-header">
            Talent Search
        </div>
                <h4 style="margin-left: 10px; color: gray;">Weight</h4>
                <fieldset id="weight">
                    <input type="checkbox" name="weight" value="1" {{WEIGHT_1}}/>Below 40<br>
                    <input type="checkbox" name="weight" value="2" {{WEIGHT_2}}/>40-70<br>
                    <input type="checkbox" name="weight" value="3" {{WEIGHT_3}}/>70-100<br>
                    <input type="checkbox" name="weight" value="4" {{WEIGHT_4}}/>Above 100<br>
                </fieldset>
                <br/>
                <input style="margin-left: 10px" type="submit" name="submit" value="search"/><br><br>
                <input type="hidden" name="tab1" value="search">
        </form>
</div>

这是我的PHP代码，

if(isset($_GET['submit'])){


    $weight = ($_GET['weight'])? $escapeObj->stringEscape($_GET['weight']): NULL;

    $sql = "SELECT id FROM `".DB_ACCOUNTS."` WHERE `id` IS NOT NULL ";

    if(is_numeric($weight) && $weight != NULL){
        $sql .= "AND `weight` IN (".$weight.")"; 
        $is_weight = true;
    }

    $sql .= " ORDER BY `id` ASC";

    }
    if($is_weight){
        $themeData['weight_'.$weight] = 'checked';
    }

    $query = $conn->query($sql);
    if($query->num_rows > 0){
            while($fetch = $query->fetch_array(MYSQLI_ASSOC)){
                $get[] = $fetch['id'];
            }

            $i = 0;
            $listResults = '';

            $themeData['page_title'] = "Advanced Search - ".$lang['search_result_header_label']; 
            foreach($get as $row){
                $timelineObj = new \SocialKit\User();
                $timelineObj->setId($row);
                $timeline = $timelineObj->getRows();

                $themeData['list_search_id'] = $timeline['id'];
                $themeData['list_search_url']   = $timeline['url'];
                $themeData['list_search_username'] = $timeline['username'];
                $themeData['list_search_name'] = $timeline['name'];
                $themeData['list_search_thumbnail_url'] = $timeline['thumbnail_url'];

                $themeData['list_search_button'] = $timelineObj->getFollowButton();

                $listResults .= \SocialKit\UI::view('search/list-each');
                $i++;
            }
            $themeData['list_search_results'] = $listResults; 

    }

}

此代码几乎适用于表中的单个权重。但我需要在代码中提到的复选框值之间创建一个范围。我是否需要更新代码。

Answer 1

在PHP代码更改

if(is_numeric($weight) && $weight != NULL){
    $sql .= "AND `weight` IN (".$weight.")"; 
    $is_weight = true;
}

要

if(is_numeric($weight) && $weight != NULL){
    if($weight==1){
        $sql .= "AND weight<40";
    }
    if($weight==2){
        $sql .= "AND weight>=40 AND weight <=70";
    }
    if($weight==3){
        $sql .= "AND weight>70 AND weight <=100";
    }
    if($weight==4){
        $sql .= "AND weight>100";
    }
    $is_weight = true;
}

另外，我强烈建议使用无线电而不是复选框，如果您选择多个权重选项，则会丢失一个值。

Answer 2

试试这个，希望这有效，所以你不会在你的代码中做出重大改变

使用radion按钮

<input type="radio" name="weight" value="0" {{WEIGHT_1}}/>Below 40<br>
<input type="radio" name="weight" value="1" {{WEIGHT_2}}/>40-70<br>
<input type="radio" name="weight" value="2" {{WEIGHT_3}}/>70-100<br>
<input type="radio" name="weight" value="3" {{WEIGHT_4}}/>Above 100<br>

您可以在php中添加变量数组

$arrayWeight = ["`weight` >= 0 && `weight` <=40", 
                "`weight` >= 40 && `weight` <=70", 
                "`weight` >=70 && `weight` <=100",
                "`weight` >= 100"];

//  $arrayWeight[$weight] = $arrayWeight[1];
//  $arrayWeight[1] = 'weight' >= 0 && 'weight' <=40    a string

在此行添加执行此操作

if(is_numeric($weight) && $weight != NULL)
    {
        $sql .= "AND ".$arrayWeight[$weight].")";  //sample $arrayWeight[1] = 'weight' >= 0 && 'weight' <=40

        //" SELECT id FROM `".DB_ACCOUNTS."` WHERE `id` IS NOT NULL AND 'weight' >= 0 && 'weight' <=40

        $is_weight = true;
    }

小心引用

如何查找复选框

2 个答案: