Question

我很难让此查询返回1行中的计数。如果没有不同年份的交易（如本例中的2016年），结果显示为1行

但是当我插入不同年份的事务然后执行此代码时，结果显示2行具有相同的结果

这是代码

select
          ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=1)AND (YEAR(date)='2017'))),0) AS `Jan`,
          ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=2)AND (YEAR(date)='2017'))),0) AS `Feb`,
          ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=3)AND (YEAR(date)='2017'))),0) AS `Mar`,
          ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=4)AND (YEAR(date)='2017'))),0) AS `Apr`,
          ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=5)AND (YEAR(date)='2017'))),0) AS `May`,
          ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=6)AND (YEAR(date)='2017'))),0) AS `Jun`,
          ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=7)AND (YEAR(date)='2017'))),0) AS `Jul`,
          ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=8)AND (YEAR(date)='2017'))),0) AS `Aug`,
          ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=9)AND (YEAR(date)='2017'))),0) AS `Sep`,
          ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=10)AND (YEAR(date)='2017'))),0) AS `Oct`,
          ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=11)AND (YEAR(date)='2017'))),0) AS `Nov`,
          ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=12)AND (YEAR(date)='2017'))),0) AS `Dec`
         from transaction GROUP BY YEAR(date)

我正在尝试在我的项目中制作年度报告，有没有办法解决这个或其他可以使其有效的查询？

Answer 1

如果您只想要2017年的数据，则应在

中过滤此数据

vswhere.exe

否则，对于您在数据中拥有的每一个，都会执行相同的ifnull（与2017相关）中的选择并返回相同的值

你可以避免使用unuseful（）和subselect，例如：

select
      ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=1)AND (YEAR(date)='2017'))),0) AS `Jan`,
      ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=2)AND (YEAR(date)='2017'))),0) AS `Feb`,
      ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=3)AND (YEAR(date)='2017'))),0) AS `Mar`,
      ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=4)AND (YEAR(date)='2017'))),0) AS `Apr`,
      ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=5)AND (YEAR(date)='2017'))),0) AS `May`,
      ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=6)AND (YEAR(date)='2017'))),0) AS `Jun`,
      ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=7)AND (YEAR(date)='2017'))),0) AS `Jul`,
      ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=8)AND (YEAR(date)='2017'))),0) AS `Aug`,
      ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=9)AND (YEAR(date)='2017'))),0) AS `Sep`,
      ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=10)AND (YEAR(date)='2017'))),0) AS `Oct`,
      ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=11)AND (YEAR(date)='2017'))),0) AS `Nov`,
      ifnull((SELECT COUNT(id) FROM (transaction)WHERE((Month(date)=12)AND (YEAR(date)='2017'))),0) AS `Dec`
     from transaction 
     where YEAR(date)='2017'
    GROUP BY YEAR(date)

Answer 2

select
SUM(Month(date)=1) AND (YEAR(date)='2017') AS `Jan`,
SUM(Month(date)=2) AND (YEAR(date)='2017') AS `Feb`,
SUM(Month(date)=3) AND (YEAR(date)='2017') AS `Mar`,
SUM(Month(date)=4) AND (YEAR(date)='2017') AS `Apr`,
SUM(Month(date)=5) AND (YEAR(date)='2017') AS `May`,
SUM(Month(date)=6) AND (YEAR(date)='2017') AS `Jun`,
SUM(Month(date)=7) AND (YEAR(date)='2017') AS `Jul`,
SUM(Month(date)=8) AND (YEAR(date)='2017') AS `Aug`,
SUM(Month(date)=9) AND (YEAR(date)='2017') AS `Sep`,
SUM(Month(date)=10) AND (YEAR(date)='2017') AS `Oct`,
SUM(Month(date)=11) AND (YEAR(date)='2017') AS `Nov`,
SUM(Month(date)=12) AND (YEAR(date)='2017') AS `Dec`
from transaction
GROUP BY YEAR(date)

您可以尝试以上代码。

这里我只是在 SUM 函数中添加了条件。如果此Month(date)=1) AND (YEAR(date)='2017'条件为true，则它将返回1，否则返回0。

所以最后它会为你提供预期的输出。

它会帮助你。

Answer 3

以下是通用查询。

SELECT COUNT(id), YEAR(created) as year, MONTH(created) as mon
FROM transaction
WHERE date IS NOT NULL
GROUP BY YEAR(date), MONTH(date) Desc

它会给出找到的所有月份的结果，以及您可以在代码中处理的缺失的月份。

IFNULL查询给出2行相同的结果

3 个答案: