我将一个对象推入另一个对象时出错。但是第二个对象是一个数组,在一个数组中有一个对象。我该如何解决这个原因我想将它添加到我的对象
中我的对象就像这样
我想将 Object2 添加到 Object1
Objet1
stdClass Object
(
[id_laporan_pemeriksa] => 5
[no_pkpt] => SNE
[tgl_pkpt] => 2010
[no_penugasan] => ST-4000/PW25/2/2017
[tgl_penugasan] => 2017-08-09
[judul_laporan] => Masukkan Kode disini
[no_laporan] => LBINA-9000/PW25/2/2017
[tgl_laporan] => 2017-08-01
[tahun_anggaran_penugasan] => 2009
[nilai_anggaran_penugasan] => 10000000
[realisasi_anggaran_penugasan] => 100000000
[jenis_anggaran_penugasan] => Utang
[sumber_laporan] => Inspektorat Maluku
[nama_sumber_penugasan] => PKPT
[nama_ketua_tim] => Abdul Rofiek, Ak.
[nama_pengendali_teknis] => Alfian Massagony, S.E.
[nama_unit_penugasan] => Irban Wil. I
[nama_penugasan] => Penjaminan
[nama_sub_penugasan] => Audit
[id_s_sub_penugasan] => 010105
[nama_s_sub_penugasan] => Audit atas hal-hal lain di bidang kepegawaian.
)
Object2的
stdClass Object
(
[id] => 3
[data_sebab] => Array
(
[0] => stdClass Object
(
[id] => 4
[data_rekomendasi] => Array
(
[0] => stdClass Object
(
[id] => 4
[data_tindak_lanjut] => Array
(
[0] => stdClass Object
(
[id] => 9
[tgl_tindak_lanjut] => 0000-00-00
)
)
)
[1] => stdClass Object
(
[id] => 5
[id_rekomendasi] =>
[data_tindak_lanjut] => Array
(
[0] => stdClass Object
(
[id] => 10
[id_tindak_lanjut] =>
[tgl_tindak_lanjut] => 0000-00-00
)
[1] => stdClass Object
(
[id] => 11
[id_tindak_lanjut] =>
[tgl_tindak_lanjut] => 0000-00-00
)
)
)
)
)
)
)
我试过了
$Object1['data']->$Object2;
但我收到了错误
无法使用stdClass类型的对象作为数组
答案 0 :(得分:4)
应该是:
$Object1->data = $Object2; // it will create data element with obj2 as value
答案 1 :(得分:3)
将#import "ARBot-Swift.h"
@interface ChatScreenViewController : JSQMessagesViewController <SpeechRecognizerDelegate>
添加为$Object2
的属性的语法是:
$Object1
或者:
$Object1->Object2 = $Object2;
答案 2 :(得分:1)
由于对象是对象而不是数组,因此使用:
$Object1['data']->$Object2;
不会工作。但是,执行以下操作将起作用:
$Object1->data = $Object2;