我有1个根项目和3个模块(api,model,storage)。 这是项目结构:
**root**
--**api**
----src
------main
--------java
----------Application.java
--------resources
----------data.csv
----build.gradle
--**model**
----src
----build.gradle
--**storage**
----src
----build.gradle
build.gradle
settings.gradle
在我的Application.java中,我试图从资源中读取CSV文件:
@SpringBootApplication
@EnableAutoConfiguration
@EnableJpaRepositories
@EnableSolrRepositories
public class MyApp{
public static void main(String[] args) throws IOException {
SpringApplication.run(MatMatchApp.class);
ClassPathResource res = new ClassPathResource("classpath:data.csv");
String path =res.getPath();
File csv = new File(path);
InputStream stream = new FileInputStream(csv);
}
}
但我得到一个例外:
Caused by: java.io.FileNotFoundException: data.csv (The system cannot find the file specified)
at java.io.FileInputStream.open0(Native Method) ~[na:1.8.0_101]
at java.io.FileInputStream.open(FileInputStream.java:195) ~[na:1.8.0_101]
at java.io.FileInputStream.<init>(FileInputStream.java:138) ~[na:1.8.0_101]
我也在尝试以下代码:
File file = new File(getClass().getResource("data.csv").getFile());
有什么建议我如何从API项目中的资源中读取文件?
解决 这段代码工作正常:
InputStream is = new ClassPathResource("/example.csv").getInputStream();
有关详细信息,请查看以下答案:Classpath resource not found when running as jar
答案 0 :(得分:2)
我在这里测试了一个正常的项目spring-boot-resource-access
您可能会错过文件前面的/
。
ClassPathResource res = new ClassPathResource("classpath:/data.csv");
或
File file = new File(getClass().getResource("/data.csv").getFile());
更新
测试您必须从像ConfigurableApplicationContext
这样的实例类中找到ClassPath的应用程序
public static void main(String[] args) throws URISyntaxException {
ConfigurableApplicationContext context = SpringApplication.run(DemoApplication.class);
File csv = new File(context.getClass().getResource("/application.properties").toURI());
System.out.println(csv.getAbsolutePath());
System.out.println(String.format("does file exists? %s", csv.exists()));
}
答案 1 :(得分:0)
这个答案帮助我解决了这个问题: Classpath resource not found when running as jar
resource.getFile()期望资源本身在文件系统上可用,即它不能嵌套在jar文件中。 您需要使用InputStream:
InputStream is = new ClassPathResource("/example.csv").getInputStream();