Question

我有这样的JSON数据，它有多个jsonArrays来解析这种类型的数据吗？

{
        "result":
        [{
        "site_name":"comenius",
        "ws_url":"https://comenius-api.sabacloud.com/v1/",
        "base_url":"https://comenius.sabacloud.com/",
        "logo_url":"",
        "Title":"",
        "menu_items":[
                {"item": 
                    [{"id":"home1","label":"Home" }]
                    },
                {"item":    
                    [{"id":"enrol1","label":"Enrollment" }]
                },
                {"item":
                   [{"id":"transcripts1","label":"Completed Courses"}]
                },
                {"item":
                   [{"id":"goals1","label":"Goals"}]
                },
                {"item":
                    [{"id":"rprojects1","label":"Reference Projects"}]
                },
                {"item":
                      [{"id":"iwh1","label":"Internal Work History"}]
                },
                {"item":
                     [{"id":"ewh1","label":"EXternal Work History"}]
                }
                ]
        },{.....}
 ]
 }

我需要解析数据并获取id，label的值，我编写一些代码来解析数据，但它没有用。

  JSONObject subObj = new JSONObject(data2);
  JSONObject innerObj1 = subObj.getJSONObject("result");
  JSONObject subArrayObj = innerObj1.getJSONObject("menu_items");
  for(int j =0;j < subArrayObj.length();j++) {
  JSONObject innsersubObj = subArrayObj.getJSONObject("item");
  String id = innsersubObj.getString("id");
  String label = innsersubObj.getString("label");
  Log.e("id",id);
  Log.e("label",label);
   }

如何解析代码中需要更改的任何内容？

Answer 1

你必须使用JSONObject和JSONArray是不同的对象，你必须使用正确的类：

JSONArray resultArray = subObj.getJSONArray("result");
JSONObject firstItem = resultArray.getJSONObject(0);
JSONArray menuItems = firstItem.getJSONArray("menu_items");

等

Answer 2

JSONARRAY subArrayObj = innerObj1.getJSONARRAY（＆＃34; menu_items＆＃34;）;

由于menu_items返回一个数组..应该在数组对象中收集..

如何解析android中有多个jsonArrays的json数据？

2 个答案: