Question

我想在第一行打印前两个字符串数组的名称，并在下一行打印剩余的名称。

<?php 
$array = array("johnny bairstow alex hales jonh marush","Marcelo nash tim pane alexender","chaudary Mian 
Muhammad Aqeel shaib ");

for ($i=0; $i < count($array) ; $i++) { 
$len = strlen($array[$i]);
$string =  $array[$i];
for ($j = 8; $j < 9 ; $j++) { 
    $string[$j] ='\n';
}


echo $string."</br>";
 }
?>

输出应该是：

johnny doe
alex hales jonh marush
Marcelo Nash
tim pane alexender
chaudary Mian 
Muhammad  Aqeel shaib

Answer 1

如果你确定数组中的字符串总数，你可以使用explode（）函数

<?php 
$array = array("johnny doe alex hales","Marcelo nash tim pane","Mian 
Muhammad Aqeel shaib");

for ($i=0; $i < count($array) ; $i++) { 
    $len = strlen($array[$i]);
    $string =  explode(" ",  $array[$i]);
    echo $string[0] . " " . $string[1] . "<br>" .
    $string[2] . " " . $string[3] . "<br>";
}
?>

注意，如果数组内没有4个字符串则返回错误

修改

执行此示例，您可以使用3个总字符串而不返回错误。我建议你使用这段代码

<?php $array = array("johnny doe alex ","Marcelo nash tim pane","Mian Muhammad Aqeel shaib"); for ($i=0; $i < count($array) ; $i++) { $len = strlen($array[$i]); $string = explode(" ", $array[$i]); for( $n=0; $n < count($string); $n++ ){ echo $string[$n]; echo ( $n & 1 ) ? '<br>' : ' ' ; } } ?>

Answer 2

试试这个：

<?php 
$array = array("johnny doe alex hales","Marcelo nash tim pane","Mian 
               Muhammad Aqeel shaib");

foreach($array as $string) {        

    foreach(explode(' ', $string) as $index => $name) {

        $br_new_string = true;

        echo $name . ' ';

        if(1 == $index % 2) {           
            echo '<br>';

            $br_new_string = false;         
        }
    }

    echo $br_new_string ? '<br>' : '';
}

输出：

johnny doe 
alex hales 
Marcelo nash 
tim pane 
Mian Muhammad 
Aqeel shaib

Answer 3

另一种简短的解决方案：

$data = ["johnny doe alex hales", "Marcelo nash tim pane", "Mian Muhammad Aqeel shaib"];

// Make them all into one string and explode the values on space
$names  = explode(' ', implode(' ', $data));

for ($i = 0; $i < count($names); $i++) {
    // Echo the name for the index, add one to the index and echo the next one.
    echo $names[$i++] . ' ' . $names[$i] . '<br />';
}

Answer 4

您可以通过查找字符串中的第二个空格，然后将其替换为您想要的内容来实现：

foreach($array as $string) 
{
    $sndSpacePos = strpos($string, ' ', strpos($string, ' ')+1); //the offset for strpos is set right after the first space so it found the second one
    echo substr($string, 0, $sndSpacePos).'<br>'.substr($string, $sndSpacePos+1).'<br>'; //echo the concatenation of string parts before and after the second space with a <br> in the middle 
}

避免使用爆炸和第二个循环。

Answer 5

array (
  0 => 'johnny bairstow',
  1 => 'alex hales jonh marush',
  2 => 'Marcelo nash',
  3 => 'tim pane alexender',
  4 => 'chaudary Mian',
  5 => 'Muhammad Aqeel shaib',
)

输出：

{{1}}

Php：想要在第一行打印前两个字符串数组的名称，并在下一行打印剩余的名称

5 个答案: