我的For
循环内部有一个相当复杂的循环,里面有一个If
语句,另外一个For
循环。并且在第二个For循环中给出了一定的标准(即If InStr(1, q.Value, "Total")
)我想结束整个If
语句并转移到Next C
。
据我所知,它像洋葱一样分层,可能没有简单的方法。
For Each C In copyRng
If IsNumeric(C) And C.Value <> "0" And Len(C) <> 0 And C.Value <> "2017" Then
Set rowRange = xSheet.Range(C, C.EntireColumn.Cells(1)) 'set range from cell up to the top cell of the comment/ Fix the 2017 thing
For Each q In rowRange 'Loop through that range and find the Account number just above it and set it as rowSrc
If InStr(1, q.Value, "C-") And Not ISIN(C, uniqueVal) Then Set rowSrc = q
If InStr(1, q.Value, "Total") Then End If 'At this point I want to leave the entire If Statement and move on to the next C
Next q
Set colSrc = C.EntireRow.Offset(0).Cells(1) 'find alert connected with the number
numCol = DestSh.Cells.Find(colSrc.Value, SearchOrder:=xlByRows, SearchDirection:=xlPrevious).Column 'look for the column in which the same alert is listed
numRow = DestSh.Cells.Find(rowSrc.Value, SearchOrder:=xlByColumns, SearchDirection:=xlPrevious).Row 'look for row in which the same account is listed
'Set destination
Set destRng = DestSh.Cells(numRow, numCol)
'Copy to destination Range
C.Copy destRng
End If
Next C
答案 0 :(得分:1)
您需要Java
,然后在循环之后,将剩余的代码放在另一个Locale.ROOT
块中:
Exit For
答案 1 :(得分:0)
删除Then
后的每个下划线并重写整个代码。逻辑改变了。你差不多按照你的想法去其他地方。
检查一下: VBA - How the colon `:` works in VBA code with condition
通常,您的代码不会像您认为的那样工作。请检查以下内容:
Public Sub TestMe()
If 1 = 2 Then _
Debug.Print "I am true - 1=2"
Debug.Print "I should be also true"
If 2 = 3 Then _
Debug.Print "I am true 2=3"
End Sub