Question

我正试图从常规表中获取常规表中的值来自ajax

中php php调用的mysql_query和mysql_fetch_array

if ($comtype==3){
        $getsteps = mysql_query("SELECT id FROM steps WHERE id = $id");

        $row = mysql_fetch_array($getsteps);
        if($row != false){
            $steps_array = array();
            while ($row = mysql_fetch_array($getsteps, MYSQL_ASSOC)) 
            {
                array_push($steps_array,$row);
            }
            $countsteps = count($steps_array);

            error_log("count: ".$countsteps);
            error_log(print_r($steps_array));

            echo json_encode(array("comtype" => $comtype, "countsteps" => $countsteps, "steps" => $steps_array)); 
        } else {
            //error
        }
    }

<{3>}错误日志中的

：

[2017年8月28日11:25:32 UTC]数：1 [28-Aug-2017 11:25:32 UTC] 1

虽然计数我知道它是2行!!!

和ajax

$.ajax({
            type:'POST',
            url:'app/check.php',
            data: {'ID':ID},
            dataType: 'json',
            success: function(value){
                if (value.comtype== "0") {
                        $("#newC").show();
                        $("#hadC").hide();
                    } else {
                        var method;
                        var com;
                        com = "<div class='clearfix'></div><br><h3>old.</h3>";
                        com += "By Stpes: <br>";

                            for (i = 0; i < value.countsteps; i++) { 
                                com += "Step " + Number(i)+1 + ": Greater Than " + value.steps_array['calfrom'] + " AND Less Than or Equal " + value.steps_array['calto'] + " Apply "  + value.steps_array['calapl'] + " % <br>";
                            }
                        }

                        $("#hadC").html(com);
                        $("#hadC").show();
                        $("#newC").hide();
                    }
                }   
            });

问题是： 1.我不知道如何将数据推送到数组中？ 2.我不知道如何在ajax中循环到这个数组，以便在html中查看它 DIV？

Answer 1

问题是您在mysql_fetch_array()循环之前调用了while。这将获取第一行，循环将获取剩余的行。

如果要在循环之前测试是否返回了任何行，请调用mysql_num_rows()。您也可以使用此代替count($steps_array)。

if ($comtype==3){
    $getsteps = mysql_query("SELECT id FROM steps WHERE id = $id");

    $countsteps = mysql_num_rows($getsteps);
    if($countsteps > 0) {
        $steps_array = array();
        while ($row = mysql_fetch_array($getsteps, MYSQL_ASSOC)) 
        {
            array_push($steps_array,$row);
        }

        error_log("count: ".$countsteps);
        error_log(print_r($steps_array));

        echo json_encode(array("comtype" => $comtype, "countsteps" => $countsteps, "steps" => $steps_array)); 
    } else {
        //error
    }
}

从mysql表获取行到php数组并将其传递给ajax

1 个答案: