Question

我有2个表叫做产品和颜色产品belongsTomany颜色和颜色belongsToMany产品使用多对多的关系现在我想在单个产品中添加更多颜色并首先检查颜色名称，如果它不存在而不是在这里创建新是我的代码

public function addproductdetailspost(Request $request, $product){
    $color_name = $request->color;
    $product = product::where('slug', $product)->firstorfail();
    $color = color::where('name', $color_name)->firstOrNew();
    $color->name = $color_name;
    $color->save();
    $product_id = $product->id;
    dd($product_id);
    $color_id = $color->id;
    $color->products()->attach($product_id);
    return Redirect::back()->with('status', 'Post Success');
}

但现在我收到错误

Type error: Too few arguments to function Illuminate\Database\Eloquent\Builder::firstOrNew()

谢谢

Answer 1

您不需要对“颜色”模型使用where方法，因为firstOrNew适用于您。

$color = color::firstOrNew(['name', $color_name]);
//$color->name = $color_name; No need s
$color->save();

Laravel 5.4 Documentation

Answer 2

我忘了添加参数

$color = color::where('name', $color_name)->firstOrCreate(['name' => $color_name]);

现在正在运作

Laravel FirstorNew（）/ FirstorCreate（）关系错误

2 个答案: