Question

我正在制作休假申请模块，我得到了＃34;用户没有属性＆＃34;错误

models.py

    from django.db import models
    from django.contrib.auth.models import User;  
    from django.db.models.signals import post_save
    from django.dispatch import receiver
    LEAVE_CHIOCE = (
    ('casual', 'Casual Leave'),
    ('vacation', 'Vacation Leave'),
    ('commuted', 'Commuted Leave'),
    ('special_casual', 'Special Casual Leave'),
    ('restricted', 'Restricted Leave'),
    ('st

ation', 'Station Leave'),
    )

    APPLICATION_STATUSES = (

    ('accepted', 'Accepted'),
    ('rejected', 'Rejected'),
    ('processing', 'Being Processed')

    )
    class Leave(models.Model):
       user = models.OneToOneField(User,related_name='applied_for', on_delete=models.CASCADE);
       leave_type = models.CharField(max_length=20, choices=LEAVE_CHIOCE);
       applied_time = models.DateTimeField(auto_now = True);
       start_date = models.DateField();
       end_date = models.DateField();
       purpose = models.CharField(max_length=500, blank=True);
       leave_address = models.CharField(max_length=100, blank=True);
       processing_status = models.CharField(max_length=20, choices=APPLICATION_STATUSES);

    @receiver(post_save, sender=User)
    def create_user_profile(sender, instance, created, **kwargs):
       if created:
          Leave.objects.create(user=instance)

    @receiver(post_save, sender=User)
    def save_user_profile(sender, instance, **kwargs):
        instance.leave.save()

forms.py

 from django import forms;
 from  . models import Leave, ApplicationRequest, RemainingLeaves;
 from django.contrib.auth.models import User;
 from django.contrib.auth.forms import UserCreationForm;
 from datetime import datetime


 class UserForm(forms.ModelForm):
    class Meta:
      model =  User;
      fields = ('username', 'first_name', 'last_name', 'email');

 class LeaveForm(forms.ModelForm):
    model = Leave;
    class Meta:
       fields = ( 'leave_type', 'start_date', 'end_date', 'purpose', 'leave_address');

view.py

from __future__ import unicode_literals
from django.contrib.auth.models import PermissionsMixin
from django.shortcuts import render
from django.http import HttpResponse;
from . models import Leave, ApplicationRequest, RemainingLeaves;
from django.contrib.auth.decorators import login_required;
from . forms import LeaveForm, UserForm;
from django.db import transaction
from django.contrib.auth.models import User
import os;


# Create your views here.
@login_required(login_url='/login')
@transaction.atomic
def getLeaveTemplate(request):
    BASE_DIR = os.path.dirname(os.path.dirname(os.path.abspath(__file__)));
    if request.method == 'POST':
        user_form = UserForm(request.POST, instance=request.user);
        leave_form = LeaveFor[enter image description here][1]m(request.POST, instance=request.user.leave)

        if user_form.is_valid() and leave_form.is_valid():
            user_form.save();
            leave_form.save();
            return HttpResponse("Thanksss");
    else:
        user_form = UserForm(instance=request.user);
        leave_form = LeaveForm(instance=request.user.leave);
    return render(request, BASE_DIR+"/templates/pages/leaveform.html", {'user_form':user_form});

Answer 1

Django文档中描述的

related_name：

用于从相关对象到此对象的关系的名称。

您在以下行声明related_name为applied_for：

user = models.OneToOneField(User, related_name='applied_for', on_delete=models.CASCADE)

这意味着Leave对象将具有用于获取相关user对象的属性User。要从User对象转到相关的Leave对象，系统会添加属性[related_name]。这是你的applied_for。要删除您的错误，只需将每个request.user.leave更改为request.user.applied_for。

要将applied_for属性更改为leave，您可以将定义更改为以下内容：

user = models.OneToOneField(User, related_name='leave', on_delete=models.CASCADE)

但related_name是一个可选参数，它有一个有用的default value：

如果没有为OneToOneField指定related_name参数，Django将使用当前模型的小写名称作为默认值。

因此，在您的情况下，不提供默认值会将属性leave添加到User个对象

# in model
user = models.OneToOneField(User, on_delete=models.CASCADE)

# in view
request.user.leave

＆＃39;用户＆＃39;对象没有属性＆＃39;离开＆＃39;

1 个答案: