不允许使用空静态前缀

时间:2017-08-28 06:14:16

标签: django python-2.7

我正在使用udemy的教程。我是关于设置静态文件on video 22, it shows how to configure static files的部分。 https://www.udemy.com/probar-django-construir-una-aplicacion-web-en-python/learn/v4/overview就是这个链接。

在视频22上显示了如何配置静态文件。

我在教程中配置了所有内容。这比仅从文档,colins,大写'POST'中键入代码更进一步。同样,我的代码与教程完全一样。

关于如何阅读错误消息的任何评论,只看看有用的 这些东西也有很好的帮助。

视频是西班牙语,但页面和代码都是英文。

任何人都可以通过查看错误消息或查看来告诉我 看看可能出错的教程。

Unhandled exception in thread started by <function wrapper at 0x034034B0>
Traceback (most recent call last):
  File "C:\Users\migel\Desktop\pd110\lib\site-
packages\django\utils\autoreload.py", line 226, in wrapper
    fn(*args, **kwargs)
  File "C:\Users\migel\Desktop\pd110\lib\site-
packages\django\core\management\commands\runserver.py", line 121, in 
inner_run
    self.check(display_num_errors=True)
  File "C:\Users\migel\Desktop\pd110\lib\site-
packages\django\core\management\base.py", line 385, in check
    include_deployment_checks=include_deployment_checks,
  File "C:\Users\migel\Desktop\pd110\lib\site-
packages\django\core\management\base.py", line 372, in _run_checks
    return checks.run_checks(**kwargs)
  File "C:\Users\migel\Desktop\pd110\lib\site-
packages\django\core\checks\registry.py", line 81, in run_checks
    new_errors = check(app_configs=app_configs)
  File "C:\Users\migel\Desktop\pd110\lib\site-
packages\django\core\checks\urls.py", line 14, in check_url_config
    return check_resolver(resolver)
  File "C:\Users\migel\Desktop\pd110\lib\site-
packages\django\core\checks\urls.py", line 24, in check_resolver
    for pattern in resolver.url_patterns:
  File "C:\Users\migel\Desktop\pd110\lib\site-
packages\django\utils\functional.py", line 35, in __get__
   res = instance.__dict__[self.name] = self.func(instance)
  File "C:\Users\migel\Desktop\pd110\lib\site-
packages\django\urls\resolvers.py", line 310, in url_patterns
    patterns = getattr(self.urlconf_module, "urlpatterns", 
self.urlconf_module)
  File "C:\Users\migel\Desktop\pd110\lib\site-
packages\django\utils\functional.py", line 35, in __get__
    res = instance.__dict__[self.name] = self.func(instance)
  File "C:\Users\migel\Desktop\pd110\lib\site-
packages\django\urls\resolvers.py", line 303, in urlconf_module
    return import_module(self.urlconf_name)
  File "c:\python27\Lib\importlib\__init__.py", line 37, in import_module
    __import__(name)
  File "C:\Users\migel\Desktop\pd110\src\pd110\urls.py", line 32, in 
<module>
    urlpatterns + static(settings.MEDIA_URL, 
document_root=settings.MEDIA_ROOT)
  File "C:\Users\migel\Desktop\pd110\lib\site-
packages\django\conf\urls\static.py", line 24, in static
    raise ImproperlyConfigured("Empty static prefix not permitted")
django.core.exceptions.ImproperlyConfigured: Empty static prefix not 
permitted

my url.py

“”“pd110网址配置

The `urlpatterns` list routes URLs to views. For more information please 
see:
https://docs.djangoproject.com/en/1.10/topics/http/urls/
Examples:
Function views
    1. Add an import:  from my_app import views
    2. Add a URL to urlpatterns:  url(r'^$', views.home, name='home')
Class-based views
    1. Add an import:  from other_app.views import Home
    2. Add a URL to urlpatterns:  url(r'^$', Home.as_view(), name='home')
Including another URLconf
    1. Import the include() function: from django.conf.urls import url, include
    2. Add a URL to urlpatterns:  url(r'^blog/', include('blog.urls'))
"""
from django.conf.urls import url
from django.conf import settings
from django.conf.urls.static import static
from django.contrib import admin

from boletin import views
#from boletin.views inicio

urlpatterns = [
    url(r'^admin/', admin.site.urls),
    url(r'^contact/$', views.contact, name='contact'),
    url(r'^$', views.inicio, name='inicio'),
]

if settings.DEBUG:
    urlpatterns += static(settings.STATIC_URL, 
document_root=settings.STATIC_ROOT)
    urlpatterns += static(settings.MEDIA_URL, 
document_root=settings.MEDIA_ROOT)

settings.py

STATIC_URL = '/static/'
STATIC_URL = '/media/'
#/static/images/img1.jpg

STATICFILES_DIRS = [
    os.path.join(BASE_DIR, "static_pro", "static"),
    #'/var/www/static/',
]

STATIC_ROOT = os.path.join(os.path.dirname(BASE_DIR), "static_env", 
"static_root")
MEDIA_ROOT = os.path.join(os.path.dirname(BASE_DIR), "static_env", 
"media_root")

4 个答案:

答案 0 :(得分:0)

如果您前往消息来源并浏览the function提出该错误,则会启动:

# django/conf/urls/static.py
def static(prefix, view=serve, **kwargs):
    ...
    if not prefix:
        raise ImproperlyConfigured("Empty static prefix not permitted")

因此,在代码中的某个时刻,您将第一个参数prefix传递给false-y(如空字符串)。查看您的urls.py,您有

urlpatterns += static(settings.STATIC_URL, document_root=settings.STATIC_ROOT)
urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)

我猜想STATIC_URLMEDIA_URL是空的。看起来你宣称是前者,所以可能是后者。

答案 1 :(得分:0)

url.py

if settings.DEBUG:
    urlpatterns += static(settings.MEDIA_URL, 
        document_root=settings.MEDIA_ROOT) + static(settings.STATIC_URL,
        document_root=settings.STATIC_ROOT)

settings.py

MEDIA_URL = '/media/'
STATIC_URL = '/static/'
#/static/imagenes/img1.jpg

STATICFILES_DIRS = [
    os.path.join(BASE_DIR, "static_pro", "static"),
    #'/var/www/static/',
]

STATIC_ROOT = os.path.join(os.path.dirname(BASE_DIR), "static_env", 
"static_root")
MEDIA_ROOT = os.path.join(os.path.dirname(BASE_DIR), "static_env", 
"media_root")

答案 2 :(得分:0)

嘿!!!似乎未创建根媒体文件夹,请先创建超级用户并创建作业,然后将自动创建该文件夹。 然后添加媒体网址“ + static(settings.MEDIA_URL,document_root = settings.MEDIA_ROOT)”。

希望!会正常工作。

答案 3 :(得分:0)

我遇到了同样的问题,所以我通读了static.py文件,它需要一个前缀...所以我做了这样的事情:

MEDIA_ROOT = os.path.join(BASE_DIR, 'media/')

然后我又重新启动并且没有错误...