Question

在本书的例子中：

https://book.cakephp.org/3.0/en/orm/associations.html#using-the-through-option

class StudentsTable extends Table
{
    public function initialize(array $config)
    {
        $this->belongsToMany('Courses', [
            'through' => 'CoursesMemberships',
        ]);
    }
}

class CoursesTable extends Table
{
    public function initialize(array $config)
    {
        $this->belongsToMany('Students', [
            'through' => 'CoursesMemberships',
        ]);
    }
}

class CoursesMembershipsTable extends Table
{
    public function initialize(array $config)
    {
        $this->belongsTo('Students');
        $this->belongsTo('Courses');
    }
}

我想在添加新grade时输入与课程＃8相对应的student。我遵循以下两个例子：

https://book.cakephp.org/3.0/en/orm/saving-data.html#saving-belongstomany-associations

和

https://book.cakephp.org/3.0/en/views/helpers/form.html#associated-form-inputs

并修改add

中的StudentsController.php方法

public function add()
    {

        $student = $this->Students->newEntity();
        if ($this->request->is('post')) {
            $student = $this->Students->patchEntity($user, $this->request->getData(), [
    'associated' => [
                'Courses']]);


            if ($this->Students->save($student,['associated' => ['Courses._joinData']])) {
                $this->Flash->success(__('The student has been saved.'));

                return $this->redirect(['action' => 'index']);
            }
            $this->Flash->error(__('The student could not be saved. Please, try again.'));
        }
        $courses = $this->Students->Courses->find('list', ['limit' => 200]);
        $this->set(compact('student', 'courses'));
        $this->set('_serialize', ['student']);
    }

和Students/add.ctp

echo $this->Form->control('courses._ids', ['options' => $courses]);
echo $this->Form->control('courses.5._joinData.grade');

当我在视图中选择课程＃8并输入相应的成绩时，我在CoursesMemberships表格中看不到它。它会添加记录本身，但grade不存在。

Answer 1

您不能将特殊_ids语法和传统语法混合用于表达嵌套数据结构，即property.index.field...（有关该行为的文档中的注释可能不会受到影响）。

同样在索引5添加数据似乎非常随意，您要添加新的链接/记录，因此通常从0开始。

抛弃_ids语法并通过明确定义其主键来构建正确的课程数据集，如：

echo $this->Form->control('courses.0.id', ['type' => 'select', 'options' => $courses]);
echo $this->Form->control('courses.0._joinData.grade');

另见

的 Cookbook > Database Access & ORM > Saving Data > Saving Additional Data to the Join Table

的 Cookbook > Views > Helpers > Form > Creating Inputs for Associated Data

Answer 2

起初我没有在你的添加功能中看到$ course ...

也许如果您将网站更改为$ courses

$ items = $ this-＆gt; Students-＆gt; Courses-＆gt; find（'list'，['limit'=＆gt; 200]）;

或在您看来：

echo $this->Form->control('courses._ids', ['options' => $items]);

在CakePHP 3.0的add方法中将其他数据保存到连接表

2 个答案: