Question

我有2个选择选项，将从不同的源动态填充，但现在我使用静态对象作为我的例子我想将原始范围内id1的volvo映射到mapme范围内id2的volvo。

一旦页面加载，如果存在类似的字段名称，它们就会被映射。到目前为止，它只是将原始范围内的id1映射到mapme范围内的id1。

任何有关如何以角度进行映射的帮助都将受到赞赏。

    angular.module('myApp',[])
    .controller('myController',function($scope,$timeout){
    $scope.original=[{"id":"id1", "text":"volvo"}, {"id":"id2", "text":"toyota"}];
    $scope.mapme=[{"id":"id1", "text":"toyota"}, {"id":"id2", "text":"volvo"}];

    });

    <div ng-app="myApp">
    <div ng-controller="myController">

    original <select ng-model="model.id" ng-options="original.id as original.text for original in original" ></select> 

    {{model.id}} 

    <br>
     mapme  <select ng-model="model.id" ng-options="map.id as map.text for map in mapme" ></select> {{model.id}}  

    </div>

</div>

Answer 1

两个模态和ng-change函数如何进行映射，但您需要访问$scope.model.id和$scope.model2.id

等ID

＆＃13;

var app = angular.module('myApp', []);

app.controller('MyController', function MyController($scope, $filter) {
$scope.model2 = "";
$scope.change = function(val){
	$scope.model2 = $filter('filter')($scope.mapme, { text: val.text })[0];
}
 $scope.original=[{"id":"id1", "text":"volvo"}, {"id":"id2", "text":"toyota"}];
    $scope.mapme=[{"id":"id1", "text":"toyota"}, {"id":"id2", "text":"volvo"}];
});

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-controller='MyController' ng-app='myApp'>
original <select ng-model="model" ng-change="change(model)" ng-options="original as original.text for original in original" ></select> 

    {{model.id}} 

    <br>
     mapme  <select ng-model="model2" ng-options="map as map.text for map in mapme" ></select> {{model2.id}}  

</div>
javascript angularjs
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edited 41 secs ago

Lazar Ljubenović
2,3331025
asked 6 mins ago

user3548161
738
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</div>

＆＃13;

AngularJS将一个选择选项映射到另一个选项

1 个答案: