Question

这是我的代码：

def contact(request):
    if request.method == 'POST':
        form = forms.ContactForm(request.POST)
        if form.is_valid():
            message = 'Thanks for your post.'
            user_name = form.cleaned_data['user_name']
            user_city = form.cleaned_data['user_city']
            user_school = form.cleaned_data['user_school']
            user_email = form.cleaned_data['user_email']
            user_message = form.cleaned_data['user_message']
            ctx = {
                'user_name':user_name,
                'user_city':user_city,
                'user_school':user_school,
                'user_email':user_email,
                'user_message':user_message,
                }
        else:
            message = 'Please check the format of your information.'
    else:
        form = forms.ContactForm()
    template = get_template('contact.html')
    request_context = RequestContext(request)
    request_context.push(locals())

    html = template.render(request_context)

    return HttpResponse(html)

但我得到以下例外：

TypeError: context must be a dict rather than RequestContext.

如何修改代码以避免此错误？（我的英语很差，对不起）

Answer 1

不推荐将Context对象传递给Template.render()。

尝试更改此内容：

request_context = RequestContext(request)
request_context.push(locals())

html = template.render(request_context)

对此：

html = template.render(context=locals(), request=request)

django1.11 TypeError：context必须是dict而不是RequestContext

1 个答案: