Question

我不确定如何将List<int>更改为指定的数组并返回每个元素。我试图创建返回数组的方法。

    using System;
    using System.Collections.Generic;

    namespace RandomArray
    {
        public class RandomArrayNoDuplicates
        {
            static Random rng = new Random();
            static int size = 45;
            static int[] ResultArray;
            static void Main()
            {
                int[] ResultArray = InitializeArrayWithNoDuplicates(size);
                Console.ReadLine();
            }


            /// <summary>
            /// Creates an array with each element a unique integer
            /// between 1 and 45 inclusively.
            /// </summary>
            /// <param name="size"> length of the returned array < 45
            /// </param>
            /// <returns>an array of length "size" and each element is
            /// a unique integer between 1 and 45 inclusive </returns>
            public static int[] InitializeArrayWithNoDuplicates(int size)
            {
                List<int> input = new List<int>();
                List<int> output;

                //Initialise Input
                for (int i = 0; i < size; i++)
                {
                    input[i] = i;
                }
                //Shuffle the array into output
                Random rng = new Random();
                output = new List<int>(input.Capacity);
                for (; input.Capacity > 0;)
                {
                    int index = rng.Next(input.Capacity);
                    int value = input[index];
                    input.Remove(index);
                    output.Add(value);
                }
                return; // Returning the final array here with each element
            }
        }
    }

是否存在List<int>类型只使用数组的等效方法，而不是使用列表然后转换回数组？我应该使用不同的系统库参考吗？

Answer 1

使用k := int16(d) - int16(r) max_k := int16(d) + int16(r) if k < 1 { k = 1 } for ; k <= max_k; k++ { ... }作为列表，如下所示：

.ToArray

反之亦然，您也可以使用list.ToArray();，

Answer 2

有，您可以随时手动交换两个数组元素而不使用任何列表：

public static void Swap<T>(T[] array, int i, int j)
{
    T temp = array[i];
    array[i] = array[j];
    array[j] = temp;
}

将List <int>更改为int []

2 个答案: