Question

我是hql的新手，我在一些网站上用来在spring框架中编写hql查询，但它会抛出＆＃34; Path期望加入！＆＃34;例外

我的查询是

"from GaugeCateSelect cs inner join PreferredUrl purl on cs.survey=purl.survey where purl.uuid=:uuid"

我想将这两个表与＆＃34; 调查＆＃34;;

连接起来

请提前帮助我解决它。

更新

两个表，名称是 GaugeCateSelect 和 PreferredUr l。＆＃34;调查＆＃34;字段对于两个表都很常见。 uuid 位于PreferredUrl中。当我将uuid传递给PreferredUrl表时，我想从GaugeCateSelect获取所有数据。（简而言之，将uuid传递给PreferredUrl，然后从PreferredUrl中找到调查编号并使用GaugeCateSelect表检查编号，如果存在则获取所有数据）

更新2

两个表之间没有主/外键引用关系。但普通实地调查有

GaugeCateSelect类

class GaugeCateSelect {

    private int id; 
    private String categoryName;    
    private int posNeg; 
    private Survey survey;  //survey is in foreign key relationship of survey table

//Annotation, getters and setters were removed for easiness.

}

PreferredUrl class

public class PreferredUrl {

    private int preferredUrlId;
    private String uuid;
    private int enabled;
    private Survey survey;  //survey is in foreign key relationship of survey table

//Annotation, getters and setters were removed for easiness.

}

Answer 1

也许您应该检查您使用的Hibernate版本，因为加入不相关的实体时存在差异，如下所述：https://www.thoughts-on-java.org/how-to-join-unrelated-entities/

hql join query：加入

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