我在咖啡脚本中得到了ajax - 它将值发送到后端。在浏览器面板中，我可以看到内部有json的响应，但是在成功的情况下 - 所有变量都是未定义的。有人可以帮忙吗？
这里是ajax的代码。
data, textStatus, jxQhr所有变量public class AssetDao implements Dao<Asset>{
public static AssetDao instance;
private String db ="deterioro";
private String assetsModule = "import module namespace assets='http://creativosdigitales.co/cartera/assets' at 'C:/Users/santiago umaña/Google Drive/Deterioro/xquery/assets.xqm';";
private String simulationsModule = "import module namespace simulations='http://creativosdigitales.co/cartera/simulations' at 'C:/Users/santiago umaña/Google Drive/Deterioro/xquery/simulations.xqm';";
public static AssetDao getInstance() {
if(instance == null) {
instance = new AssetDao();
}
return instance;
}
@Override
public List<Asset> get() throws IOException, JAXBException {
List<Asset> results = new ArrayList<Asset>();
try(BaseXClient session = new BaseXClient("localhost", 1984, "admin", "admin")){
session.execute("open "+db);
final String xquery = "for $data in subsequence(//asset, 1, 20) return <asset> {$data/assetid} {$data/payment} {$data/pendingpayments} <balance>{ format-number($data/balance, \"#.00\") }</balance> <npv>{ format-number(sum(//simulation[assetid=$data/assetid]/payment/npv), \"#.00\") }</npv> <difference>{ format-number($data/balance - sum(//simulation[assetid=$data/assetid]/payment/npv), \"#.00\") }</difference> </asset>";
JAXBContext context = JAXBContext.newInstance(Asset.class);
Unmarshaller unmarshaller = context.createUnmarshaller();
Query query = session.query(xquery);
while(query.more()) {
results.add((Asset) unmarshaller.unmarshal(new StringReader(query.next())));
}
return results;
}
}
//custom methods
public List<ExtraField> getExtraFields(String assetId) throws IOException, JAXBException {
List<ExtraField> extraFields = new ArrayList<ExtraField>();
try(BaseXClient session = new BaseXClient("localhost", 1984, "admin", "admin")){
final String xquery = assetsModule
+ "let $db := collection('"+db+"')"
+ "let $asset := assets:asset-info($db, '"+assetId+"')"
+ "return assets:extra-fields($asset)";
JAXBContext context = JAXBContext.newInstance(ExtraField.class);
Unmarshaller unmarshaller = context.createUnmarshaller();
Query query = session.query(xquery);
System.out.println(query.toString());
while(query.more()) {
extraFields.add((ExtraField) unmarshaller.unmarshal(new StringReader(query.next())));
}
return extraFields;
}
}
public List<Simulation> getSimulation(String assetId) throws IOException, JAXBException {
List<Simulation> simulations = new ArrayList<Simulation>();
try(BaseXClient session = new BaseXClient("localhost", 1984, "admin", "admin")){
final String xquery = assetsModule
+ simulationsModule
+ "let $db := collection('"+db+"')"
+ "let $asset := assets:asset-info($db, '"+assetId+"')"
+ "return simulations:simulation-xml($asset)";
JAXBContext context = JAXBContext.newInstance(Simulation.class);
Unmarshaller unmarshaller = context.createUnmarshaller();
Query query = session.query(xquery);
System.out.println(query.toString());
while(query.more()) {
simulations.add((Simulation) unmarshaller.unmarshal(new StringReader(query.next())));
}
return simulations;
}
}
都是未定义的。我如何从这些变量中获取这些值？
答案 0 :(得分：1)
你应该查看你正在尝试做的文档：
这是执行帖子的两种方式，但它们有不同的方法签名。
就像在评论中所说，你在这里有的是不同语法的混合，这两种语法都无效。
在大多数情况下，它看起来像$.ajax签名，所以你可以稍微改变它（注意我还修复了缩进 - 尝试在问题中发布代码时正确，因为它是对于像coffeescript这样的语言很重要：
# Note i'm using string interpolation, not concatenation
$.ajax "/articles/#{id}/comments",
# add this key-val to determine the request type
method: "POST"
contentType: 'application/json'
data: comment_params:
commenter: commenter
body: body
success: (data, textStatus, jQxhr) ->
console.log(textStatus)
$('#comments').append JSON.stringify(data)
dataType: 'json'