Question

我的asynctask有问题加载url的内容，内容有时间加载到字符串，我被迫做Thread.Sleep等待内容加载，我确定是不是ri ght方式，所以我问你什么是没有那个内容的正确方法

我的AsynTask：

package fungames.fungames;

import android.os.AsyncTask;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.params.CoreProtocolPNames;
import org.apache.http.util.EntityUtils;


class GetContent extends AsyncTask<String, Void, String> {
    protected  String result = "";
     protected  int done = 0;

     @Override
    protected String doInBackground(String[] params) {

        try {
            DefaultHttpClient httpClient = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost(params[0]);
            httpClient.getParams().setParameter(CoreProtocolPNames.USER_AGENT, "FGAPP");
         HttpResponse resulte = httpClient.execute(httpPost);
            HttpEntity entity = resulte.getEntity();
          result = EntityUtils.toString(entity,"UTF-8");
        }
        catch(Exception i) {
            result = i.toString();
        }
        done = 1;
        return result;

    }

    protected void onPostExecute(String message) {
    }
}

我的Loader：

public static void Example() {
  String values = Servers.Load();
}
 public static String Load() {
        String url = "http://example.com";
        GetContent job = new GetContent();
        job.execute(url);
        return Do2(job);
    }
 public static String Do2(GetContent job)
        {
            String game = job.result;
            if (game != "") {
                    return game;
                }
            } else {
                try {
                    Thread.sleep(50);
                } catch (Exception e) {
                    e.printStackTrace();
                }
                return Do2(job);
            }
        }

谢谢你！

Answer 1

在AsyncTask类中创建一个接口：

class GetContent extends AsyncTask<String, Void, String> {

protected  String result = "";
 protected  int done = 0;  
protected String action = "";

public interface SendResult {
    void onTaskFinished(String result,String action);
  }  

public SendResult resultInterface = null;

public GetContent(SendResult interface,String action){
    resultInterface  = interface;
    this.action = action;
}
 @Override
protected String doInBackground(String[] params) {

    try {
        DefaultHttpClient httpClient = new DefaultHttpClient();
        HttpPost httpPost = new HttpPost(params[0]);
        httpClient.getParams().setParameter(CoreProtocolPNames.USER_AGENT, "FGAPP");
     HttpResponse resulte = httpClient.execute(httpPost);
        HttpEntity entity = resulte.getEntity();
      result = EntityUtils.toString(entity,"UTF-8");
    }
    catch(Exception i) {
        result = i.toString();
    }
    done = 1;
    return result;

}

protected void onPostExecute(String message) {
    resultInterface.onTaskFinished(message,action);
}
}

在您的活动中实施该界面：

public class MainActivity extends AppCompatActivity 
implements GetContent.SendResult{

@Override
public void onCreate(Bundle savedInstanceState) {

    String url = "http://example.com";
    fetchDataForUrl(url,"RequestType-1");
}  

public void fetchDataForUrl(String url,String action){
    GetContent job = new GetContent(this,action);
    job.execute(url);
}


@Override
void onTaskFinished(String result,String action){
    //Here you will receive the result.  
    //Do what ever you want here.
      if(action.equals("RequestType-1")){
           //access result here.
        }
    }
}

是时候从url android加载内容了

1 个答案: