Question

这种格式我需要我不想使用\ n或br，因为我的字符串是动态的，我想用这种格式修复任何文本

    This is my first textview
        This is my second 
          textview this 
           is my third
            textview

Answer 1

此处没有默认实现。此外，您无法找到执行此操作的行号。因此，您必须将句子拆分为多行。使用\n作为下一行。将重心设置为 textView 。

Answer 2

   if you use \n then your next line will be start from      

   This is my first textview
   <here> 
        <not here>

所以，基本上你需要多个TextViews。

首先将您的文本字符串分配给多个部分（注意： - （n + 1）部分应小于第n个部分，deff。应该是两个结束空间）。

秒创建具有垂直方向和中心重力的LinearLayout。

该阵列上的

第三次循环。并在循环中创建一个带有重心的新文本视图，并将文本设置为它。并将此电视添加到linearLayout。

就是这样。

Answer 3

我试着按你的意愿给你结果

这可能有用

<强> activity_main.xml中

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:app="http://schemas.android.com/apk/res-auto"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:gravity="center"
    tools:context="com.ap.mytestingapp.MainActivity">

    <TextView
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:id="@+id/strTV"
        android:text="hello world!"
        android:gravity="center" />

</RelativeLayout>

<强> MainActivity.java

import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.widget.TextView;

public class MainActivity extends AppCompatActivity {

    private TextView tv;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        tv = (TextView) findViewById(R.id.strTV);

        //pass string whatever you want to show
        String apStr = printString("This is my first textview This is my second textview this is my third textview");

        //you need to define text size according to your requirement
        // I took here 25

        tv.setTextSize(25);
        tv.setText(apStr);
    }

    private String printString(String responseString) {

        String str = responseString;
        String resultStr = "";

        //you need to define cutLength Value according to your textView's textSize
        // I took it 35 when textView's textSize is 25

        int cutLength = 35;
        int count = 0;
        int from = 0;

        for(int i = 0 ; i < str.length(); i++){

            //increment of count
            count++;

            //check count value with cutLength so that we can add \n to string
            if(count == cutLength){

                // adding \n to substring
                resultStr = resultStr + str.substring(from, i) + "\n";

                // assigning from = i
                from = i;

                // reduce cutLength value
                cutLength = cutLength-10;

                // assigning count = 0
                count = 0;

            } else if(i == str.length()-1){

                // adding \n to substring
                resultStr = resultStr + str.substring(from) + "\n";
            }

        }

        //return resulting string
        return resultStr;
    }
}

Answer 4

您可以使用此功能以编程方式执行此操作

val text = "This is my first text view this is my second textview this is my third textview"
textView.text = proxyWifi.textFormation(text)

复制/粘贴此代码执行您的项目：）

public String textFormation(String text){
    String result = "";
    String[] sentenceWords = text.split(" ");
    List<String> newSentenceWords = new ArrayList<>();
    textRec(sentenceWords, newSentenceWords, sentenceWords.length -1, 0, "");

    int spacing = 0;
    for(int i = newSentenceWords.size() -1 ; i >= 0 ; i--){
        if(i == newSentenceWords.size() -1)
            result = newSentenceWords.get(i);
        else{
            result += "\n";
            spacing += (newSentenceWords.get(i + 1).length() - newSentenceWords.get(i).length())/2;

            for(int j = 0 ; j < spacing ; j++){
                result += " ";
            }

            result += newSentenceWords.get(i);
        }
    }

    return result;

}

public void textRec(String[] words, List<String> newWords, int indexWords, int indexNewWords, String sentence){
    Log.e("sentence", sentence);
    if(indexWords >= 0){
        if(indexNewWords == 0) {
            newWords.add(words[indexWords]);
            textRec(words, newWords, indexWords - 1, ++indexNewWords, "");
        }else{
            if(newWords.get(indexNewWords - 1).length() >= sentence.length())
                if(sentence.isEmpty())
                    textRec(words, newWords, indexWords - 1, indexNewWords, words[indexWords]);
                else
                    textRec(words, newWords, indexWords - 1, indexNewWords,  words[indexWords] + " " + sentence);
            else {
                newWords.add(sentence);
                textRec(words, newWords, indexWords , ++indexNewWords, "");
            }
        }
    }else{
        if(sentence.isEmpty()){
            return;
        }else{
            newWords.set(indexNewWords - 1 ,sentence + " " + newWords.get(indexNewWords - 1)) ;
        }
    }
}

<强>输出

如何在不使用\ n或html格式的情况下在android中格式化单个textview如下？

4 个答案: