Question

我需要声明一个类型（带有typedef），这是指向2D数组的char指针。

typedef char* board {
    char* arr[8][8];
}chessboard;

但它不会编译。我也找到了这个：

typedef char board[8][8];

这可行，但它实际上并不是指向数组的指针。我很感激任何想法，谢谢。

Answer 1

做

typedef char (*BoardPointer)[8][8]

将BoardPointer定义为指向char的8x8数组的类型，所以

BoardPointer boardpointer;

将boardpointer定义为指向char的8x8数组的指针。

要分配一个8x8 char的数组，您可以这样做：

BoardPointer boardpointer = malloc(sizeof *boardpointer);
if (NULL == boardpointer)
{
  perror("malloc() failed");
}
else
{
  // use boardpointer here. Set all elements to '\0' for example:
  for (size_t r = 0; r < 8)
  {
    for (size_t c = 0; c < 8)
    {
      (*boardpointer)[r][c] = '\0';
    }
  }

  free(boardpointer);
}

正如其他人指出typedef指针容易出错并且使代码难以阅读，您也可以这样做：

typedef char Board[8][8]

Board * boardpointer = malloc(sizeof *boardpointer);
if (NULL == boardpointer)
{
  perror("malloc() failed");
}
else
{
  // use board here. Set all elements to '\0' for example:
  for (size_t r = 0; r < 8)
  {
    for (size_t c = 0; c < 8)
    {
      (*boardpointer)[r][c] = '\0';
    }
  }

  free(boardpointer);
}

或只是

typedef char Board[8][8]

Board board;
// use board here. Set all elements to '\0' for example:
for (size_t r = 0; r < 8)
{
  for (size_t c = 0; c < 8)
  {
    board[r][c] = '\0';
  }
}

Typedef指向2D数组的指针

1 个答案: