Question

这是我的代码，它不会产生任何输出。因为我从100开始循环所以根据使用的逻辑，我应该得到答案为153.但没有任何事情发生。请帮忙。

// Program to find the first Angstrom Number and display it!
public static void main(String[] args) {
    int sum = 0;
    int y, z;
    System.out.println("Starting program");

    for (int i = 100; i < 1000; i++) {
        sum += (i % 10) * (i % 10) * (i % 10);
        y = i / 10;
        sum += (y % 10) * (y % 10) * (y % 10);
        z = y / 10;
        sum += z * z * z;
        if (sum == i) {
            System.out.println("The first Angstrom number is " + i);
            break;
        }
    }
}

Answer 1

您应该在每个步骤中重置总和：

for (int i = 100; i < 1000; i++) {
    sum = 0;
    sum += (i%10) * (i%10) * (i%10);
    ....
}

Answer 2

使用此逻辑，您可以在两个数字之间找到阿姆斯壮数字。只需根据需要更改值即可。

public class Armstrong {

    public static void main(String[] args) {

        int low = 999, high = 99999;

        for(int number = low + 1; number < high; ++number) {
            int digits = 0;
            int result = 0;
            int originalNumber = number;

            // number of digits calculation
            while (originalNumber != 0) {
                originalNumber /= 10;
                ++digits;
            }

            originalNumber = number;

            // result contains sum of nth power of its digits
            while (originalNumber != 0) {
                int remainder = originalNumber % 10;
                result += Math.pow(remainder, digits);
                originalNumber /= 10;
            }

            if (result == number)
                System.out.print(number + " ");
        }
    }
}

该程序的输出为：
1634 8208 9474 54748 92727 93084

Answer 3

public static int Power(int out,int res)
{
    int count=res;
        int temp=1;
        while(count!=0)
        {
            temp=temp*out;
            count--;
        }
        return temp;
}
public static int count1(int num)
{
    int count=0;
    while(num!=0)
    {
        num=num/10;
        count++;
    }
    return count;
}
public static int isArmstrong(int num)
{
    int out;
    int sum=0;
    int res=count1(num);
    while(num!=0)
    {
        out=num%10;
        sum=sum+Power(out,res);
        num=num/10;
    }
    return sum;
}
public static void  main(String[] args)
{
    int start=10;
    int end=100000;
    for(int i=start;i<=end;i++)
    {
    int result=isArmstrong(i);
    if(result==i)
    {
        System.out.println(i);
    }

Java中的阿姆斯特朗号

3 个答案: