我得到了第一个(主要)数组,如下所示,
$groceritems = array(
"apple" => array(
"price"=>"10",
"origin"=>array("australia","belgium","USA","canada"),
"breed"=>array("gala","fuji","Honeycrisp","washington"),),
"orange" => array(
"price"=>"10",
"origin"=>array("australia","belgium","USA","canada"),
"breed"=>array("gala","fuji","Honeycrisp","washington"),
),
);
foreach ($groceritems as $key => $value) {
$origins = $value['origin'];
$breeds= $value['breed'];
foreach (array_combine($origins, $breeds) as $origin=>$breed) {
echo $breed ." ".$key." from ". $origin ." price is RM ". $value['price'];
echo "<br>";
}
}
第二个数组如下,
$grocer= array(
"apple" => array( "country"=>"australia",
"newprice"=>"50",
"breed"=>"gala"),
"orange" => array("country"=>"belgium",
"newprice"=>"30",
"breed"=>"gala"),
);
我能够循环第一个数组但是如何将第一个数组的价格(在foreach循环中)替换为newprice,条件类别(orange / apple),country和breed匹配的第二个数组? 如下结果,
来自澳大利亚的嘎拉苹果价格为RM 50 来自比利时的富士苹果价格是RM 10来自美国的Honeycrisp苹果价格为RM 10
来自加拿大的华盛顿苹果价格为RM 10来自澳大利亚的gala orange价格为RM 10
来自比利时的富士橙价格为RM 10来自美国的Honeycrisp橙色价格为RM 10
来自加拿大的华盛顿橙色价格为RM 10答案 0 :(得分:0)
要获得所需的结果,请执行以下操作
$groceritems = array(
"apple" => array(
"price"=>"10",
"origin"=>array("australia","belgium","USA","canada"),
"breed"=>array("gala","fuji","Honeycrisp","washington"),),
"orange" => array(
"price"=>"10",
"origin"=>array("australia","belgium","USA","canada"),
"breed"=>array("gala","fuji","Honeycrisp","washington"),
),
);
$grocer= array(
"apple" => array( "country"=>"australia",
"newprice"=>"50",
"breed"=>"gala"),
"orange" => array("country"=>"belgium",
"newprice"=>"30",
"breed"=>"gala"),
);
foreach ($groceritems as $key => $value) {
$origins = $value['origin'];
$breeds= $value['breed'];
foreach (array_combine($origins, $breeds) as $origin=>$breed) {
if(isset($grocer[$key]) && $origin == $grocer[$key]['country'] && $breed == $grocer[$key]['breed'] ){
$price = $grocer[$key]['newprice'];
} else {
$price = $value['price'];
}
echo $breed ." ".$key." from ". $origin ." price is RM ". $price;
echo "<br>";
}
}