Question

不久前开始编码，大约一个月左右。我目前正在为Discord编写机器人，一切正常，直到我在添加新命令后尝试运行机器人时收到此错误消息：

Traceback (most recent call last):
  File "C:\Users\Jeriel\Desktop\JerryBot\run.py", line 162, in main
    from musicbot import MusicBot
  File "C:\Users\Jeriel\Desktop\JerryBot\musicbot\__init__.py", line 1, in <modu
le>
    from .bot import MusicBot
  File "C:\Users\Jeriel\Desktop\JerryBot\music\bot.py", line 2094
    if __name__ == "__main__":
                             ^
IndentationError: unexpected unindent

在我添加之后就开始了。我在这之前检查了每一行，我无法在任何地方找到一个单独的：

    async def kick(message,*args):
        """Kicks the specified user from the server"""
        if len(message.mentions) < 1:
            return False

        if message.channel.is_private:
            msg = await client.send_message(message.channel,'Users cannot be kicked/banned from private channels.')
            asyncio.ensure_future(message_timeout(msg, 40))
            return

        if not message.channel.permissions_for(message.server.get_member(client.user.id)).kick_members:
            msg = await client.send_message(message.channel, message.author.mention + ', I do not have permission to kick users.')
            asyncio.ensure_future(message_timeout(msg, 40))
            return

        members = []

        if not message.channel.is_private and message.channel.permissions_for(message.author).kick_members:
            for member in message.mentions:
                if member != message.author:
                    try:
                        await client.kick(member)
                        members.append(member.name)
                    except:
                        pass
                else:
                    msg = await client.send_message(message.channel, message.author.mention + ', You should not kick yourself from a channel, use the leave button instead.')
                    asyncio.ensure_future(message_timeout(msg, 40))
        else:
            msg = await client.send_message(message.channel, message.author.mention + ', I do not have permission to kick users, or this is a private message channel.')
            asyncio.ensure_future(message_timeout(msg, 40))

        msg = await client.send_message(message.channel,'Successfully kicked user(s): `{}`'.format('`, `'.join(members)))
        asyncio.ensure_future(message_timeout(msg, 60))

    @register('ban','@<mention users>',owner=True)

    async def ban(message,*args):
        """Bans the specified user from the server"""
        if len(message.mentions) < 1:
            return False

        if message.channel.is_private:
            msg = await client.send_message(message.channel,'Users cannot be kicked/banned from private channels.')
            asyncio.ensure_future(message_timeout(msg, 40))
            return

        if not message.channel.permissions_for(message.server.get_member(client.user.id)).ban_members:
            msg = await client.send_message(message.channel, message.author.mention + ', I do not have permission to ban users.')
            asyncio.ensure_future(message_timeout(msg, 40))
            return

        members = []

        if message.channel.permissions_for(message.author).ban_members:
            for member in message.mentions:
                if member != message.author:
                    try:
                        await client.ban(member)
                        members.append(member.name)
                    except:
                        pass
                else:
                    msg = await client.send_message(message.channel, message.author.mention + ', You should not ban yourself from a channel, use the leave button instead.')
                    asyncio.ensure_future(message_timeout(msg, 40))
        else:
            msg = await client.send_message(message.channel, message.author.mention + ', I do not have permission to ban users, or this is a private message channel.')
            asyncio.ensure_future(message_timeout(msg, 40))

        msg = await client.send_message(message.channel,'Successfully banned user(s): `{}`'.format('`, `'.join(members)))
        asyncio.ensure_future(message_timeout(msg, 30))

    @register('bans',alias='bannedusers')
    @register('bannedusers')


if __name__ == "__main__":
    bot = JerryBot()
    bot.run("---")

Answer 1

你的问题在这里：

    @register('bans',alias='bannedusers')
    @register('bannedusers')


if __name__ == "__main__":
    bot = JerryBot()
    bot.run("---")

装饰器语法需要@行下的函数定义，该行必须与@处于同一缩进级别。换句话说，你不能在那里发表if声明。你需要一个函数定义。缩进只是它抓住的第一个问题;如果您缩进if语句，则会出现其他错误。

我无法判断您是否在此处包含错误的@行，或者您是否省略了要置于此处的函数定义。编写函数或删除@行，以符合您的目的。

Answer 2

你有可能混合标签和空格吗？对于初学者来说，这是一个常见的错误。从技术上讲，您可以使用其中任何一种，但不能混用它们。我的解决方案（我使用vim作为IDE）是将tab键设置为我的.vimrc中实际为4个空格。

您可以通过输入gg=G并在命令模式下按Enter键来尝试在vim中重新设置。

IndentationError：意外的unindent

2 个答案: