Question

如果我玩了一轮游戏并选择退出选项，则游戏结束，但是，如果我玩第二轮并尝试退出，则游戏继续并提示用户再次输入猜测，而不是终止游戏。

似乎陷入了困境。

这是我的代码：

from random import randint
def core_game():

    def init_hangman():
        hangman = []

        for x in range(7):
            hangman.append([" "] * 7)
        hangman[0][0] = "_"
        hangman[0][1] = "_"
        hangman[0][2] = "_"
        hangman[1][3] = "|"
        return hangman

    hangman = init_hangman()

    def print_hangman():
        for x in hangman:
            print(str.join("", x))

    def get_input(guess):
            your_guess = input(guess)
            if your_guess in guessed_letters:
                print("You already guessed that letter!")
                return get_input(guess)
            elif your_guess.isalpha() and len(your_guess) == 1:
                return your_guess
            else:
                print("Please guess a single letter!")
                return get_input(guess)

    words_list = ["monkey", "cow"]
    city_list = ["Amarillo", "Houston"]
    lists = ["animals", "cities"]
    random_list = randint(0,1)
    random_word = randint(0,1)
    if lists[random_list] == "cities":
        rand_list = city_list
    elif lists[random_list] == "animals":
        rand_list = words_list
    word = rand_list[random_word]
    guessed = ""
    guessed_letters = []
    hang = 6
    Cont = True

    for letter in word:
        guessed += "-"

    print("\n\n\nWELCOME TO HANGMAN!")    
    print("The category is: ", lists[random_list])
    print("The secret word: ", guessed, "is", len(guessed), "letters")

    while Cont:
        your_guess = get_input("\nEnter your guess: ")
        if your_guess in word.lower():           
            for x in range(len(word)):
                if word[x].lower() == your_guess.lower():
                    guessed = guessed[:x] + word[x] + guessed[x+1:]
            guessed_letters.append(your_guess)
            print("\nThe secret word: ", guessed)
            if guessed.lower() == word.lower():
                print("\n\nCongratulations, you guessed the word!")
                play_again = input("\nWould you like to play again?(y/n) ")
                if play_again == "y" or play_again == "yes":
                    core_game()
                else:
                    Cont = False

        else:
            hang -= 1
            guessed_letters.append(your_guess)
            print("\nGuessed letters: ", guessed_letters)
            if hang == 5:
                hangman[2][3] = "O"
                print_hangman()
                print(guessed)
            elif hang == 4:
                hangman[3][3] = "|"
                print_hangman()
                print(guessed)
            elif hang == 3:
                hangman[3][2] = "-"
                print_hangman()
                print(guessed)
            elif hang == 2:
                hangman[3][4] = "-"
                print_hangman()
                print(guessed)
            elif hang == 1:
                hangman[4][2] = "/"
                print_hangman()
                print(guessed)
            elif hang == 0:
                hangman[4][4] = "\\"
                print_hangman()
                print("Game Over!")
                print("The word was: ", word)
                play_again = input("Would you like to play again?(y/n) ")
                if play_again == "y" or play_again == "yes":
                    core_game()
                else:
                    Cont = False


core_game()

主要功能是core_game（），并在程序运行时调用它。

Answer 1

好的 - 是的，我喜欢这款游戏 - 在浏览器中播放trinket.io

然后我走了整个游戏here。使用它来逐步调试代码，您可以查看所有变量，列表等，以及输入输入和视图输出。

你的游戏重复的原因是：

1）在函数 core_game 中，您有以下代码：

if play_again == "y" or play_again == "yes":
    core_game()

这意味着当您在第一个游戏之后选择“是”时，您将打开该功能的另一个“实例” - 如果您浏览代码，则可以看到此实例。您也可以在下面的屏幕截图（f19）中看到这一点。

2）在你玩第二个游戏后（记住第一个实例仍然打开）并选择“n”，这会导致“Cont”变量更改为False，但仅在第二个实例中。然后关闭“while”，代码返回到Cont仍为True的第一个实例。您还可以在屏幕截图中看到这两个实例，以及“Cont”的每个值的状态。封闭的框架是“灰色的”。

3）程序在while循环开始时在core_game的第一个实例中恢复，并提示用户输入猜测。

在您浏览代码之前很难看到，但我在这里包含了一个快照，您可以（我希望）看到我的意思。

所以问题是你从内部调用函数。

考虑更像这样的事情：

def core_game():
    print("I was called")


while Cont:
    ans = ("Do you wish to play a game? (Y/N)")
    if ans[0].lower() == "y":  # works for Y, y, Yup, Yeah, Yes etc.
        core_game()
    else:
        Cont = False

PS 还有其他非常好的参考资料来源，例如this。

永远不要放弃 - 你会发现步入式非常方便，你可以在稍后的阶段尝试Rice Course MOOC on Coursera。

玩完一轮之后尝试退出后在蟒蛇中的刽子手游戏

1 个答案: