Question

Acts-as-Taggable-on无法正确打印出name列，而不是对象本身的整个信息散列。如何设置显示页面以分别打印模型的每个标签？我到目前为止的代码如下。

show.html.erb

<%= @user.user_profile.tags.each do |tag| %>
<%= tag.name %>
<% end %>

结果显示在显示页面

#<ActsAsTaggableOn::Tag::ActiveRecord_Associations_CollectionProxy:0x2b7534d0> games [#<ActsAsTaggableOn::Tag id: 1, name: "games", created_at: "2017-08-25 15:54:30", updated_at: "2017-08-25 15:54:30", taggings_count: 1>] 1

控制台输出

 Rendering users/show.html.erb within layouts/application
  UserProfile Load (8.0ms)  SELECT  "user_profiles".* FROM "user_profiles" WHERE "user_profiles"."user_id" = $1 LIMIT $2  [["user_id", 5], ["LIMIT", 1]]
  ActsAsTaggableOn::Tag Load (15.0ms)  SELECT "tags".* FROM "tags" INNER JOIN "taggings" ON "tags"."id" = "taggings"."tag_id" WHERE "taggings"."taggable_id" = $1 AND "taggings"."taggable_type" = $2 AND "taggings"."context" = $3  [["taggable_id", 2], ["taggable_type", "UserProfile"], ["context", "tags"]]
  ActsAsTaggableOn::Tagging Load (2.0ms)  SELECT "taggings".* FROM "taggings" WHERE "taggings"."taggable_id" = $1 AND "taggings"."taggable_type" = $2  [["taggable_id", 2], ["taggable_type", "UserProfile"]]
  ActsAsTaggableOn::Tag Load (25.0ms)  SELECT "tags".* FROM "tags" INNER JOIN "taggings" ON "tags"."id" = "taggings"."tag_id" WHERE "taggings"."taggable_id" = $1 AND "taggings"."taggable_type" = $2 AND (taggings.context = 'tags' AND taggings.tagger_id IS NULL)  [["taggable_id", 2], ["taggable_type", "UserProfile"]]

user_profile.rb

class UserProfile < ApplicationRecord
  acts_as_taggable
  acts_as_taggable_on :abilities
end

Answer 1

尝试

<% @user.user_profile.tags.each do |tag| %>
  <%= tag.name %>
<% end %>

（没有＆＃39; =＆＃39;在第一行的＆＃39;＆lt;％＆＃39;之后）

Acts-as-Taggable-On显示哈希对象而不是标记名称

1 个答案: