如何将混合维数阵列展平为二维列表?

时间:2017-08-25 13:17:17

标签: python list flatten

我知道有很多关于我如何压扁二维列表的帖子但是这个有点不同,因为它是二维和三维列表的混合:

items = [[255, 204, 204], ..., [255, 179, 179], [[250, 250, 250], ..., [220, 220, 220]]]

我希望此列表仅为二维:

items = [[255, 204, 204], ..., [255, 179, 179], [250, 250, 250], ..., [220, 220, 220]]

我尝试使用列表理解,但它没有正确地压缩列表:

flat_list = [item for items in l for item in items]

将混合维数阵列展平为二维数组的最佳方法是什么?

4 个答案:

答案 0 :(得分:5)

old_list = [[255, 204, 204], [255, 179, 179], [['250, 250, 250'], ['220, 220, 220']]]                                                                                                         
new_list = []  
for i in old_list:
    if isinstance(i[0], list):
        for j in i:
            new_list.append(j)
    else:
        new_list.append(i)
print new_list

输出结果为:

[[255, 204, 204], [255, 179, 179], ['250, 250, 250'], ['220, 220, 220']]

答案 1 :(得分:3)

您可以使用递归函数:

create function GetOnlyCharacters
(
    @SearchVal varchar(8000)
) returns table as return

    with MyValues as
    (
        select substring(@SearchVal, N, 1) as number
            , t.N
        from cteTally t 
        where N <= len(@SearchVal)
            and substring(@SearchVal, N, 1) like '[a-z]'
    )

    select distinct NumValue = STUFF((select number + ''
                from MyValues mv2
                order by mv2.N
                for xml path('')), 1, 0, '')
    from MyValues mv

演示:

def flatten(items):
    for item in items:
        if isinstance(item[0], list):
            yield from flatten(item)
        else:
            yield item

答案 2 :(得分:1)

from itertools import chain

items = [[255, 204, 204], [255, 179, 179], [['250, 250, 250'], ['220, 220, 220']]]

flat_list = list(chain.from_iterable(lst if isinstance(lst[0], list) else [lst] for lst in items))

print(flat_list)
>>> [[255, 204, 204], [255, 179, 179], ['250, 250, 250'], ['220, 220, 220']]

答案 3 :(得分:0)

def tree2matrix(T):
  if T == []:
    return []
  elif type(T) is not list:
    return [[T]]
  elif type(T[0]) is not list:
    return [T]
  else:
    return tree2matrix(T[0]) + tree2matrix(T[1:])

X = [[255, 204, 204], [255, 179, 179], [['250, 250, 250'], ['220, 220, 220']]]
print(tree2matrix(X))