Question

这是我的表格：

+---------------------+--------+----------+
| date                | sku    | quantity |
+---------------------+--------+----------+
| 2017-08-23 14:58:00 | 123333 |        2 |
| 2017-08-23 14:58:00 | 123333 |        1 |
| 2017-08-23 14:58:00 | 123333 |        1 |
| 2017-08-23 14:58:00 | 123337 |        2 |
| 2017-08-23 14:58:00 | 123335 |        1 |
| 2017-08-23 14:58:00 | 123331 |        1 |
| 2017-08-23 14:58:00 | 123332 |        2 |
| 2017-08-23 14:58:00 | 123333 |        1 |
| 2017-08-23 14:58:00 | 123334 |        1 |
| 2017-08-23 14:58:00 | 123334 |        3 |
+---------------------+--------+----------+

我想按如下方式执行select语句：

select sku,sum(quantity) as 'total quant' from transactions
where DATE(date) between '2017-07-23' and '2017-09-23'
group by sku
order by quantity desc;

但我得到了这个：

+--------+-------------+
| sku    | total quant |
+--------+-------------+
| 123332 | 2           |
| 123337 | 2           |
| 123333 | 5           |
| 123334 | 4           |
| 123335 | 1           |
| 123331 | 1           |
+--------+-------------+

这不符合我的预期。 为什么订单不在这里工作？

SIDE NOTE 我的quantity列的数据类型为int，我已根据this post中的建议尝试投放但无效。

Answer 1

您按数量订购。因为它没有聚合，所以您从每个组中获取任意值。你需要按总额订购。一种方法是：

order by sum(quantity) desc

但是，我建议指定一个合理的别名（一个不需要转义的别名）并使用它：

select sku,sum(quantity) as total_quantity
from transactions
where DATE(date) between '2017-07-23' and '2017-09-23'
group by sku
order by total_quantity desc;

Answer 2

您需要按SUM(quantity)订购。

SELECT sku, SUM(quantity) AS 'total quant' 
FROM transactions
WHERE DATE(date) BETWEEN '2017-07-23' AND '2017-09-23'
GROUP BY sku
ORDER BY SUM(quantity) DESC;

Answer 3

您应该使用：

exclude

SQL ORDER BY - 为什么它不能在这里工作？

3 个答案: