Spring安全性hasPermission无效

时间:2017-08-25 09:21:38

标签: java spring spring-mvc spring-security

我正在尝试将Spring Security集成到我的Spring应用程序中。基本上我需要根据用户权限隐藏一些菜单。这就是我所做的。

我在类路径中添加了JARS。

spring-security-acl-4.0.2.RELEASE.jar
spring-security-config-4.0.2.RELEASE.jar
spring-security-core-4.0.2.RELEASE.jar
spring-security-taglibs-4.0.1.RELEASE.jar
spring-security-web-4.0.2.RELEASE.jar

以下是web.xml中的条目

<context-param>
    <param-name>log4jConfiguration</param-name>
    <param-value>/WEB-INF/web_log4j.xml</param-value>
</context-param>

<listener>
    <listener-class>org.apache.logging.log4j.web.Log4jServletContextListener</listener-class>
</listener>

<servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring-root.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

我写了一个类CustomPermissionEvaluator,如下所示。

public class CustomPermissionEvaluator implements PermissionEvaluator{


@Override
public boolean hasPermission(Authentication authentication, Object targetDomainObject, Object permission) {
    HttpServletRequest request = (HttpServletRequest) targetDomainObject;
    Profile userProfile = (Profile) request.getSession().getAttribute("testprofile");
    if (userProfile.getPermissionMap().get(String.valueOf(permission)) != null) {
        return true;
    } else {
        return false;
    }
}

@Override
public boolean hasPermission(Authentication arg0, Serializable arg1,
        String arg2, Object arg3) {
    // TODO Auto-generated method stub
    return false;
}

}

在此之后我编写了SecurityConfig文件。

@Configuration
@EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {

@Override
public void configure(WebSecurity web) throws Exception {
    DefaultWebSecurityExpressionHandler handler = new DefaultWebSecurityExpressionHandler();
    handler.setPermissionEvaluator(new CustomPermissionEvaluator());
    web.expressionHandler(handler);
}

}

我的spring-root.xml中有以下条目

<sec:global-method-security pre-post-annotations="enabled">
    <sec:expression-handler ref="expressionHandler" />
</sec:global-method-security>
<bean id="expressionHandler"
    class="org.springframework.security.access.expression.method.DefaultMethodSecurityExpressionHandler">
    <property name="permissionEvaluator" ref="permissionEvaluator" />
</bean>
<bean id="permissionEvaluator" class="main.java.com.config.CustomPermissionEvaluator" />

现在在我的JSP文件中,我在taglib下面使用。

及以下代码

<sec:authorize access="hasPermission('cadastra_categoria', #request)">      
                <div id="TEST">
                </div>
            </sec:authorize>

但它不起作用。任何建议将不胜感激。

3 个答案:

答案 0 :(得分:2)

  

&#34; hasPermission(&#39; cadastra_categoria&#39;,#request;&#34;

实际上,有效调用必须交换参数,第一个必须是目标域对象,第二个 - 权限:

hasPermission(#request, 'cadastra_categoria')

我假设您还仔细检查了您已根据需要将sec taglib导入您的JSP

<%@ taglib prefix="sec" uri="http://www.springframework.org/security/tags" %>

最后,正如本answer的第二部分所阐明的那样,定义以下内容:

import org.springframework.web.servlet.support.AbstractAnnotationConfigDispatcherServletInitializer;

public class AnnotationConfigDispatcherServletInitializer extends
    AbstractAnnotationConfigDispatcherServletInitializer {

  @Override
  protected Class<?>[] getRootConfigClasses() {
    return new Class[] {
      SecurityConfig.class //your SecurityConfig
    };
  }
}

确保在您的Web应用程序启动期间调用configure(WebSecurity web)

答案 1 :(得分:2)

据我了解您的问题,您已创建了CustomPermissionEvaluator课程,但未使用经过身份验证的用户权限进行检查。

我正在直接编写代码 CustomPermissionEvaluator ,以表明我的观点可能有任何错误:

public class CustomPermissionEvaluator implements PermissionEvaluator {

    public boolean hasPermission(Authentication auth, Object targetDomainObject, Object permission) {
        if ((auth == null) || (targetDomainObject == null) || !(permission instanceof String)){
            return false;
        }

        Profile userProfile = (Profile) request.getSession().getAttribute("testprofile");
        String targetType = userProfile.getPermissionMap().get(String.valueOf(permission));

        return hasPrivilege(auth, targetType, permission.toString().toUpperCase());
    }

    private boolean hasPrivilege(Authentication auth, String targetType, String permission) {
        for (GrantedAuthority grantedAuth : auth.getAuthorities()) {
            if (grantedAuth.getAuthority().startsWith(targetType)) {
                if (grantedAuth.getAuthority().contains(permission)) {
                    return true;
                }
            }
        }
        return false;
    }

    @Override
    public boolean hasPermission(Authentication arg0, Serializable arg1, String arg2, Object arg3) {
        // TODO Auto-generated method stub
        return false;
    }
}

答案 2 :(得分:0)

请尝试hasAnyRole并检查一次,即

<sec:authorize access="hasAnyRole('ROLE_NAME')"> TEST </sec:authorize>