Question

如果满足以下条件但我不断收到语法错误

，我需要这个返回一个布尔值

declare @OverLimit bit = 0  
declare @var int

set @var = Select count(pkid)
             From Clicks

If @var > 720,000 then
  @OverLimit = 1

Select @OverLimit

Answer 1

以下是修正了语法错误的版本：

declare @OverLimit bit = 0 declare @var int

set @var = (Select count(pkid) From Clicks)

If @var > 720000 SET @OverLimit = 1

Select @OverLimit

问题是：

set - select语句需要括号

保留逗号（删除它）

Answer 2

您可以尝试阅读SQL手册，错误消息并处理基础语法问题：

declare @OverLimit bit
set     @Overlimit = 0

declare @var int
select  @var = count(pkid) From Clicks

If @var > 720000 set @OverLimit = 1

select @OverLimit

Answer 3

试试这个：

declare @OverLimit bit = 0
declare @var int

SELECT @var = count(pkid) From Clicks

If @var > 720000 SET @OverLimit = 1

Select @OverLimit

或者：

SELECT CASE WHEN COUNT(pkid) > 720000 THEN CAST(1 AS bit) ELSE CAST(0 AS bit) END AS Overlimit
FROM Clicks

Answer 4

希望我在编写测试时能够访问SQL：但这不是错误的

set @var = Select count(pkid) From Clicks

试

 Select @var=count(pkid) From Clicks

Answer 5

由于您未列出特定错误，因此我建议修改一些行。

改变自：

set @var = Select count(pkid) from Clicks

要：

set @var = (Select count(pkid) from Clicks)

从720,000
从If语句中删除“then”并插入“Set”：
```
If @var > 720000
   set @OverLimit = 1
```

SQL：使用变量

5 个答案: