Question

我正在制作购物车，当用户将商品添加到购物车时，它会保存到数据库中。我已在标签中放置了所有必需的信息。一些信息以纯文本和隐藏输入重复。问题是当我向购物车添加商品时，它确实说“已添加商品”，但实际上并未向数据库添加任何信息。我已经测试过它是由图像还是价格等造成的。只有当我只留下order_quantity时，它才会按预期运行。

以下是商店页面：

<!DOCTYPE html>
<html>

    <head>
        <title>Store</title>
        <link href="../styles/main.css" rel="stylesheet" type="text/css"/>
    </head>

    <body>
        <header>
            <center><img src="../images/logo.png"></a></center>

            <nav>
                <ul>
                    <center><h3><li>Store</li>
                    <li><a href="cart.php">Cart</a></li>
                    <li><a href="userorders.php">My orders</a></li>
                    <li><a href="logout.php">Logout</a></li></h3></center>
                </ul>
            </nav>
        </header>

        <div class="left">
            <ul>
                <h4><li>Completes</li>
                <li><a href="decksstore.php">Decks</li>
                <li><a href="wheelsstore.php">Wheels</a></li>
                <li><a href="bearingsstore.php">Bearings</a></li>
                <li><a href="trucksstore.php">Trucks</a></li>
                <li><a href="hardwarestore.php">Hardware</a></li></h4>
            </ul>
        </div>


        <div class="main">
        <br>
            <?php
                require_once('../../connect.php');

                $select = "SELECT * FROM tblcompletes";
                $response = mysqli_query($dbc, $select);

                while ($row = mysqli_fetch_array($response))
                {

                    echo '<div class="buyproducts">  
                        <form method="post" action="addtocart.php">
                            <div style="border:1px solid white; background-color:white; border-radius:20px; padding:20px;" align="center">  
                                <img src="data:image/jpeg;base64,'.base64_encode( $row['product_image'] ).'" class="img-responsive">
                                <h4 class="text-info">'.$row['product_name'].'</h4>
                                <h4 class="text-danger">$'.$row['product_price'].'</h4>
                                <h4>'.$row['product_quantity'].' in stock</h4> 
                                Quantity: <input type="text" name="order_quantity" class="form-control" value="1">  
                                <input type="hidden" name="hidden_id" value="'.$row["product_ID"].'">
                                <input type="hidden" name="hidden_image" value="data:image/jpeg;base64,'.base64_encode( $row['product_image'] ).'" class="img-responsive">
                                <input type="hidden" name="hidden_name" value="'.$row["product_name"].'">
                                <input type="hidden" name="hidden_price" value="'.$row["product_price"].'">
                                <input type="submit" style="margin-top:5px;" class="btn-success" value="Add to cart">
                            </div>
                        </form>
                    </div>';

                }
            ?>
        </div>
    </body>

</html>

这是行动档案：

<?php
    require_once('../../connect.php');

    $hidden_id = $_POST['product_ID'];
    $hidden_image = $_POST['product_image'];
    $hidden_name = $_POST['product_name'];
    $hidden_price = $_POST['product_price'];
    $order_quantity = $_POST['order_quantity'];
    $user_email = $_COOKIE['user_email'];

    if ($order_quantity == NULL) 
    {
        echo '<script type="text/javascript"> alert("Please enter a valid value"); window.location="completesstore.php"; </script>';
    }

    else
    {
        $addtocart = "INSERT INTO tblorders (product_ID, product_iamge, product_name, product_price, order_quantity, user_email) VALUES (?, ?, ?, ?, ?, ?)";
        $stmt = mysqli_prepare($dbc, $addtocart);
        mysqli_stmt_bind_param($stmt, "issdis", $hidden_id, $hidden_image, $hidden_name, $hidden_price, $order_quantity, $user_email);
        mysqli_stmt_execute($stmt);

        echo '<script type="text/javascript"> alert("Item added"); window.location="completesstore.php"; </script>';

    }

    mysqli_st_close($stmt);
    mysqli_close($dbc);
?>

提前致谢。

Answer 1

更改

$hidden_id = $_POST['product_ID'];
$hidden_image = $_POST['product_image'];
$hidden_name = $_POST['product_name'];
$hidden_price = $_POST['product_price'];
$order_quantity = $_POST['order_quantity'];
$user_email = $_COOKIE['user_email'];

要

$hidden_id = $_POST['hidden_id'];
$hidden_image = $_POST['hidden_image'];
$hidden_name = $_POST['hidden_name'];
$hidden_price = $_POST['hidden_price'];
$order_quantity = $_POST['order_quantity'];
$user_email = $_COOKIE['user_email'];

name中使用的

form属性在 addtocart.php 文件中有所不同。

Answer 2

使用以下代码更新您的操作文件：

$hidden_id = $_POST['product_ID'];
$hidden_image = $_POST['product_image'];
$hidden_name = $_POST['product_name'];
$hidden_price = $_POST['product_price'];
$order_quantity = $_POST['order_quantity'];
$user_email = $_COOKIE['user_email'];

将上述代码替换为：

$hidden_id = $_POST['hidden_id'];
$hidden_image = $_POST['hidden_image'];
$hidden_name = $_POST['hidden_name'];
$hidden_price = $_POST['hidden_price'];
$order_quantity = $_POST['order_quantity'];
$user_email = $_COOKIE['user_email'];

Answer 3

在按钮示例中添加一些名称：

<input type="submit" style="margin-top:5px;" class="btn-success" value="Add to cart" name="Submit">

然后到你的addtocart.php添加：

if(isset($_Submit['Submit'])){
$hidden_id = $_POST['product_ID'];
$hidden_image = $_POST['product_image'];
$hidden_name = $_POST['product_name'];
$hidden_price = $_POST['product_price'];
$order_quantity = $_POST['order_quantity'];
$user_email = $_COOKIE['user_email'];}

并确保您已连接到数据库。

无法将信息从表单存储到数据库

3 个答案: