Python继承 - 对象没有属性错误

时间:2017-08-24 22:22:58

标签: python inheritance

我正在尝试使用继承自Animal类的Dog类进行基本的python继承。出于某种原因,我的Dog对象未正确继承name并且我不断获得AttributeError: 'Dog' object has no attribute '_Dog__name'。有谁知道可能会发生什么?我的代码如下:

class Animal(object):
    __name = None #signifies lack of a value
    __height = 0
    __weight = 0
    __sound = 0

    def __init__(self, name, height, weight, sound):
        self.__name = name
        self.__height = height
        self.__weight = weight
        self.__sound = sound


class Dog(Animal):
    def __init__(self, name, height, weight, sound, owner):

        super(Dog, self).__init__(name, height, weight, sound)

        self.__owner = owner
        #self.__name = name this works if I uncomment this line.

    __owner = ""

    def toString(self):
        return "{} belongs to {}".format(self.__name, self.__owner)
        #return 'Sup dawg'

fido = Dog("Spot", 3, 4, "Woof", "John")

print(fido.toString())

1 个答案:

答案 0 :(得分:4)

__ - 前缀属性名称的目的是破坏它们,以便子类无法轻松访问它们,以防止它们被意外覆盖。该错误消息显示父类如何破坏名称,因此您可以直接使用它:

def toString(self):
    return "{} belongs to {}".format(self._Dog__name, self.__owner)

但你真的应该省去前缀并使用常规名称。另外,不要定义toString方法;请改用__str__。类级别的初始值设定项也是不必要的。

class Animal(object):
    def __init__(self, name, height, weight, sound):
        self.name = name
        self.height = height
        self.weight = weight
        self.sound = sound

class Dog(Animal):
    def __init__(self, name, height, weight, sound, owner):
        super(Dog, self).__init__(name, height, weight, sound)
        self.owner = owner

    def __str__(self):
        return "{} belongs to {}".format(self.name, self.owner)

fido = Dog("Spot", 3, 4, "Woof", "John")
print(fido)  # print will convert fido to a string implicitly, using its __str__ method