Question

我尝试使用几个帮助表来显示计时器的状态。（用php浏览器）辅助表用于在语言之间切换。

这里是Timer Types的辅助表：

+-------------+------+------------------+
| lfdLanguage | Type | TText            |
+-------------+------+------------------+
|           0 |    0 | Puls             |
|           0 |    1 | steigende Flanke |
|           0 |    2 | fallende Flanke  |
|           1 |    0 | Pulse            |
|           1 |    1 | rissing edge     |
|           1 |    2 | falling edge     |
+-------------+------+------------------+

和Day Active：

+-------------+--------+--------+
| lfdLanguage | Active | ACText |
+-------------+--------+--------+
|           0 |      0 | _      |
|           0 |      1 | X      |
|           1 |      0 | _      |
|           1 |      1 | X      |
+-------------+--------+--------+

通常我使用equi连接，但在这里我想使用相同的帮助表来显示日期的状态（即RunMonday，...）。

在没有AND WHERE HTT.lfdLanguage = 0的情况下使用以下语句可以正常工作。

但是我可以通过where声明来执行。我收到一个错误：

（＆＃39; ERROR 1064（42000）：.....＆＃39;）

SELECT DISTINCT
  T.lfdTimer,
  T.Active,
  T.Name,
  T.Type,         HTT.TText,
  T.RunMonday,    HTDA1.ACText,
  T.RunTuesday,   HTDA2.ACText,
  T.RunWednesady, HTDA3.ACText,
  T.RunThursday,  HTDA4.ACText,
  T.RunFriday,    HTDA5.ACText,
  T.RunSaturday,  HTDA6.ACText,
  T.RunSunday,    HTDA7.ACText
FROM
  Timer T
INNER JOIN HelpTimerType      HTT   ON (T.Type         = HTT.Type     AND  WHERE HTT.lfdLanguage = 0);
 LEFT JOIN HelpTimerDayActive HTDA1 ON (T.RunMonday    = HTDA1.Active)
 LEFT JOIN HelpTimerDayActive HTDA2 ON (T.RunTuesday   = HTDA2.Active)
 LEFT JOIN HelpTimerDayActive HTDA3 ON (T.RunWednesady = HTDA3.Active)
 LEFT JOIN HelpTimerDayActive HTDA4 ON (T.RunThursday  = HTDA4.Active)
 LEFT JOIN HelpTimerDayActive HTDA5 ON (T.RunFriday    = HTDA5.Active)
 LEFT JOIN HelpTimerDayActive HTDA6 ON (T.RunSaturday  = HTDA6.Active)
 LEFT JOIN HelpTimerDayActive HTDA7 ON (T.RunSunday    = HTDA7.Active) 
;

知道如何将语言选择包含在JOIN中吗？

所有帮助表示赞赏。感谢

Answer 1

where子句在所有连接之后：

SELECT DISTINCT T.lfdTimer, T.Active, T.Name, T.Type, HTT.TText, T.RunMonday, HTDA1.ACText, T.RunTuesday, HTDA2.ACText, T.RunWednesady, HTDA3.ACText, T.RunThursday, HTDA4.ACText, T.RunFriday, HTDA5.ACText, T.RunSaturday, HTDA6.ACText, T.RunSunday, HTDA7.ACText FROM Timer T INNER JOIN HelpTimerType HTT ON (T.Type = HTT.Type) LEFT JOIN HelpTimerDayActive HTDA1 ON (T.RunMonday = HTDA1.Active) LEFT JOIN HelpTimerDayActive HTDA2 ON (T.RunTuesday = HTDA2.Active) LEFT JOIN HelpTimerDayActive HTDA3 ON (T.RunWednesady = HTDA3.Active) LEFT JOIN HelpTimerDayActive HTDA4 ON (T.RunThursday = HTDA4.Active) LEFT JOIN HelpTimerDayActive HTDA5 ON (T.RunFriday = HTDA5.Active) LEFT JOIN HelpTimerDayActive HTDA6 ON (T.RunSaturday = HTDA6.Active) LEFT JOIN HelpTimerDayActive HTDA7 ON (T.RunSunday = HTDA7.Active) WHERE HTT.lfdLanguage = 0 ;

Answer 2

删除

WHERE

来自你的内连接，这是错误的语法。

使用具有多个条件的多个JOIN

2 个答案: