Question

有没有办法从1开始计算数组的键并计算到数组的结尾（下例中为10）。因此，如果选中所有复选框，则结果应为55（1 + 2 + 3 ... + 10）。我从1开始分配了密钥，但它没有工作。这就是我到目前为止所拥有的。这是数组（值现在无关紧要，稍后会处理）：

<?php  
$rank1_1[1] = '<input type = "checkbox"  name = "v_1[]" value="1" />h';
$rank1_1[2] = '<input type = "checkbox"  name = "v_1[]" value="7" />w';
$rank1_1[3] = '<input type = "checkbox"  name = "v_1[]" value="20" />n';
$rank1_1[4] = '<input type = "checkbox"  name = "v_1[]" value="44" />m';
$rank1_1[5] = '<input type = "checkbox"  name = "v_1[]" value="81" />l';
$rank1_1[6] = '<input type = "checkbox"  name = "v_1[]" value="133" />k';
$rank1_1[7] = '<input type = "checkbox"  name = "v_1[]" value="203" />p';
$rank1_1[8] = '<input type = "checkbox"  name = "v_1[]" value="292" />b';
$rank1_1[9] = '<input type = "checkbox"  name = "v_1[]" value="403" />s';
$rank1_1[10] = '<input type = "checkbox"  name = "v_1[]" value="537" />b';
 ?>

过程：

<?php
for ($i = 1; $i <= count($rank1_1); $i++)
echo $rank1_1[$i], '<br />';  
$keys = array_keys($checked_1);
foreach($keys as $keys_s) {
$keys_sum +=  $keys_s;
  } 
?>

结果：

<?php 
 echo '<br />$keys_sum  = '. $keys_sum; // $keys_sum = 45
 print_r ($keys_sum); // Array ( [0] => 0 [1] => 1 [2] => 2 [3] => 3 
 [4] => 4 [5] => 5 [6] => 6 [7] => 7 [8] => 8 [9] => 9 )
?>

此外，如果我检查第8，第9和第10个框，结果是：

Array ( [0] => 0 [1] => 1 [2] => 2 [3]

如何让它按预期工作？请帮忙。

Answer 1

假设$ rank1_1数组中的每个键值对都被视为＆＃34;检查＆＃34;，那么你的答案很简单：

$rank1_1[1] = '<input type = "checkbox"  name = "v_1[]" value="1" />h';
$rank1_1[2] = '<input type = "checkbox"  name = "v_1[]" value="7" />w';
$rank1_1[3] = '<input type = "checkbox"  name = "v_1[]" value="20" />n';
$rank1_1[4] = '<input type = "checkbox"  name = "v_1[]" value="44" />m';
$rank1_1[5] = '<input type = "checkbox"  name = "v_1[]" value="81" />l';
$rank1_1[6] = '<input type = "checkbox"  name = "v_1[]" value="133" />k';
$rank1_1[7] = '<input type = "checkbox"  name = "v_1[]" value="203" />p';
$rank1_1[8] = '<input type = "checkbox"  name = "v_1[]" value="292" />b';
$rank1_1[9] = '<input type = "checkbox"  name = "v_1[]" value="403" />s';
$rank1_1[10] = '<input type = "checkbox"  name = "v_1[]" value="537" />b';

echo array_sum( array_keys( $rank1_1 ) ); // 55

echo '<br />';
echo '<br />';

但是如果您需要确保在$ checked_1中检查值，那么我只能假设您的值为1,7,20,44等。

$checked_1 = array( 1, 7, 20, 44 );

在这种情况下，你需要像这样匹配：

$i = 1;
foreach( $rank1_1 as $key => $value )
{
    foreach( $checked_1 as $x )
    {
        if( strpos( $value, 'value="' . $x . '"') !== FALSE )
        {
            $found[] = $i;
            $i++;
            break;
        }
    }
}

if( isset( $found ) )
    echo array_sum( $found ); // 10

尽管如此，如果任何$ checked_1元素只是添加到您的计数中，并且总是从1开始，那么您可能只是这样做：

$total = 0;
for( $x = 1; $x <= count( $checked_1 ); $x++ )
{
    $total += $x;
}

如果这些都没有帮助你，我想你需要举例说明$ checked_1的样子，以及你的期望是什么。

更新-----------------

关于你最近的评论，你的意思是这样的：

foreach( $rank1_1 as $key => $value )
{
    foreach( $checked_1 as $x )
    {
        if( strpos( $value, 'value="' . $x . '"') !== FALSE )
        {
            $found[] = $x;
            break;
        }
    }
}

if( isset( $found ) )
    echo array_sum( $found );

更新2 --------------------

键的总和：

foreach( $rank1_1 as $key => $value )
{
    foreach( $checked_1 as $x )
    {
        if( strpos( $value, 'value="' . $x . '"') !== FALSE )
        {
            $found[] = $key;
            break;
        }
    }
}

if( isset( $found ) )
    echo array_sum( $found );

从1开始获取数组的键并计数

1 个答案: