我在laravel中有一个包含此字段的表单:
<form>
<input type='text' name="title">
<input type='file' name="files">
</form>
In server side, I done some proccess on files.
$imagesUrl = $this->uploadImages($request->file('files'));
DD($ imagesUrl):
array:2 [▼
"images" => array:4 [▼
"original" => "/upload/images/2017/10453717_202487510125261_45876946_n.jpg"
300 => "/upload/images/2017/300_10453717_202487510125261_45876946_n.jpg"
600 => "/upload/images/2017/600_10453717_202487510125261_45876946_n.jpg"
900 => "/upload/images/2017/900_10453717_202487510125261_45876946_n.jpg"
]
"thumb" => "/upload/images/2017/300_10453717_202487510125261_45876946_n.jpg"
]
现在我想用$imagesUrl
替换$request->file('files')
并在数据库中插入新记录。
我试试这个:
auth()->user()->article()->create(array_merge($request->all() , [ 'files' => $imagesUrl]));
但是我收到了这个错误:
(1/1)ErrorException数组到字符串转换
我错了什么?
答案 0 :(得分:0)
你应该试试这个:
$imagesUrl = serialize($imagesUrl);
$arrInsert = ['title'=> $request->title,'files'=>$imagesUrl];
auth()->user()->article()->create($arrInsert);
再次检索它然后反序列化
$imagesUrl = unserialize($raw->files);
答案 1 :(得分:0)
答案:我在模态中添加了此代码
protected $casts = [
'files' => 'array'
];