Question

我有以下存储在json文件中的JSON数据，这个JSON的架构不同，所以这个问题不重复： -

为什么跟随PHP生成“NULL”？： -

<?php

$url  = "file.json";
echo $url . "<br>";

$json_string = file_get_contents($url);
echo $json_string . "<br>";

$json_array = json_decode($json_string, true); // need an associative array
var_dump(json_decode($json_array));

?>

问题：如果“代码”：“XXX”存在，如何在PHP中找到“city”，“state”和“region”的值： -

 [
  {
    "code": "XXX",
    "city": "Indore",
    "state": "Madhya Pradesh",
    "region": "W"
  },
  {
    "code": "XXY",
    "city": "Vapi",
    "state": "Gujarat",
    "region": "W"
  },
  {
    "code": "XXZ",
    "city": "Kolkata",
    "state": "West Bengal",
    "region": "E"
  },
  {
    "code": "XXV",
    "city": "Sundar Nagar",
    "state": "Himachal Pradesh",
    "region": "N"
  }
 ]

Answer 1

尝试以下代码。首先解码json然后循环它

$json = '[
  {
    "code": "XXX",
    "city": "Indore",
    "state": "Madhya Pradesh",
    "region": "W"
  },
  {
    "code": "XXY",
    "city": "Vapi",
    "state": "Gujarat",
    "region": "W"
  },
  {
    "code": "XXZ",
    "city": "Kolkata",
    "state": "West Bengal",
    "region": "E"
  },
  {
    "code": "XXV",
    "city": "Sundar Nagar",
    "state": "Himachal Pradesh",
    "region": "N"
  }
 ]';
 $arr = json_decode($json,true);
 $find_val = "XXX";
 $city = $region =$state = "";
 foreach ($arr as $key => $value) {
   if($value['code'] == $find_val)
   {
    $city = $value['city'];
    $state =$value['state'];
    $region = $value['region'];
   }
 }
 echo $city;
 echo "<br>";
 echo $state;
 echo "<br>";
 echo $region;

在PHP中从JSON文件中查找键及其值

1 个答案: