Question

我需要将一个数量（Number）分解为组件，例如，58963的数量将分为50000,8000,900,60和3，如何在sql中使用函数实现这一点，任何想法？

此致

伊尔凡

Answer 1

尝试

DECLARE @amount INT = 58963
DECLARE @temp INT
DECLARE @i INT = 0

DECLARE @tempStore TABLE(val int)

WHILE(@amount>0)
BEGIN
    SET @temp = @amount % 10;
    SET @amount = @amount /10;
    INSERT INTO @tempStore VALUES(@temp * POWER(10, @i))
    SET @i = @i+1;
END

SELECT * FROM @tempStore ORDER BY val DESC

如果值不适合整数范围，则可以使用bigint代替int。

如果要获得逗号分隔输出，请尝试

DECLARE @amount BIGINT = 589625
DECLARE @temp BIGINT
DECLARE @i INT = 0

DECLARE @tempStore TABLE(val BIGINT)

WHILE(@amount>0)
BEGIN
    SET @temp = @amount % 10;
    SET @amount = @amount /10;
    INSERT INTO @tempStore VALUES(@temp * POWER(10, @i))
    SET @i = @i+1;
END

DECLARE @tmp VARCHAR(MAX)= ''
select @tmp = @tmp + CONVERT(VARCHAR(100), val ) + ', ' from @tempStore ORDER BY val DESC

select SUBSTRING(@tmp, 0, LEN(@tmp))

如果你想用数据库方式而不是通用编程逻辑（不想要WHILE循环）来实现它，那么你可以尝试

DECLARE @amount AS INT = 58963;
;WITH cte
      AS ( SELECT  1 AS n, @amount AS m, 1 as p, 1 as r
           UNION ALL
           SELECT  (cte.m%10), (cte.m / 10), (cte.p*10), ((cte.m%10) * (cte.p*10))/10
           FROM cte
           WHERE cte.m > 0
         )

SELECT cte.r --,*
FROM    cte WHERE (cte.n*cte.p)/10 > 0
--ORDER BY cte.r DESC

Answer 2

对于SQL Server

DECLARE @num INT = 58963;

with decList as
(
  select 10 AS decNum
  union all
  select decNum  * 10 AS dt
  from decList
  where decNum  <= @num
)
select CASE WHEN decNum > 10 
            THEN ((@num % decNum) / (decNum / 10)) * (decNum / 10)
            ELSE @num % decNum
       END
from decList

Answer 3

这适用于任何数字。

DECLARE @amount AS INT = 58963;

WITH    cte
          AS ( SELECT   1 AS n
               UNION ALL
               SELECT   cte.n * 10
               FROM     cte
               WHERE    cte.n < @amount / 10
             )
    SELECT  ( ( @amount % ( cte.n * 10 ) ) / cte.n ) * cte.n
    FROM    cte;

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