Question

我有两张桌子.College_Infra_items和College_infrastructure。College_Infra_items有以下结构

    col_infraId  requiredSeat   available      collegeInfrastructureId
       1         100              150                   1
       2         200              180                   2

College_infrastructure有以下结构

    collegeInfrastructureId  type    name
         1                   UGC     Land Requirement(In acres)
         2                   UGC     Class rooms
         3                   AICTE   Total Area
         4                   AICTE   Loans

现在在我加载的html中，我正在重复College_infrastructure的详细信息。我正在为类型编写条件。如果它是UGC类型，那么College_infrastructure的前两行详细信息将加载。如果AICTE接下来两个。这是我的HTML

在表格格式中，我显示详细信息。在tbody部分，我只重复了“name”列的College_infrastructure表。但是我无法获取requiredSeat的详细信息并且可用，因为在查询中我没有使用College_infraItem表执行连接操作。

    <tbody>
    <tr role="row" class="even" data-ng-repeat="infraitem in 
    allInfraitemsByType">
    <td><strong>{{infraitem.name}}</strong></td>
    <td><input type="text"  
    name="requiredseat" data-ng-model="infraitem.requiredseat"></td>
    <td>
    <input type="text" name="available" data-ng-
    model="infraitem.available"></td>
    <td class="text-center"><button type="submit" class="btn GreenBtn" 
    data-ng-click="saveInfrastructureDetails(infraitem)"><span 
    class="glyphicon glyphicon-ok"></span>Save</button></td>
    </tr>
    </tbody>

在查询中我写的是这样的

    SELECT collegeInfrastructureId as collegeInfrastructureId,type as 
    type,name as name FROM college_infrastructure where type=:type
    order by collegeInfrastructureId asc";

这个查询只给我一个College_Infrastructure表。但是我也想在同一个查询中找到College_Infra_items的详细信息。任何人都可以告诉我如何使用此查询加入College_Infra_items，以便在html重复中我也可以参考College_Infra_items列。

Answer 1

SELECT ci.collegeInfrastructureId as collegeInfrastructureId,ci.type as 
type,ci.name as name ,
   cli.requiredSeat   
   ... and some more fields you need
FROM college_infrastructure ci
   LEFT JOIN College_Infra_items cli ON cli.collegeInfrastructureId=ci.collegeInfrastructureId
where type=:type
order by ci.collegeInfrastructureId asc";

只需在查询中的第二个表中使用INNER JOIN。

更新。将INNER JOIN更改为LEFT JOIN

Answer 2

试试这个：

SELECT college_infrastructure.collegeInfrastructureId as collegeInfrastructureId,college_infrastructure.type as type,college_infrastructure.name as name ,College_Infra_items.requiredSeat 
FROM college_infrastructure left join College_Infra_items  on College_Infra_items.collegeInfrastructureId = college_infrastructure.collegeInfrastructureId
where type=:type
order by collegeInfrastructureId asc";

在angularjs中显示多个数据

2 个答案: