select ds.school_name_np,
case
when (ds.gender_id = 1 and ds.class=1) then ds.no_of_student
end as boys_1,
case
when (ds.gender_id = 2 and ds.class=1) then ds.no_of_student
end as girls_1,
case
when (ds.gender_id = 1 and ds.class=2) then ds.no_of_student
end as boys_2,
case
when (ds.gender_id = 2 and ds.class=2) then ds.no_of_student
end as girls_2
from data_047_differntly_abled_school_summary ds
-- GROUP BY school_name_np, gender_id, class, no_of_student
ORDER BY school_name_np
我有上面的查询生成如下结果:
如何在同一行中获得同一所学校的成绩?
答案 0 :(得分:1)
只需在每列上使用聚合函数:
select ds.school_name_np,
MAX(case when ds.gender_id = 1 and ds.class=1 then s.no_of_student end) as boys_1,
MAX(case.....),
...
from data_047_differntly_abled_school_summary ds
GROUP BY school_name_np
ORDER BY school_name_np