Question

我是编码的新手，我试着写一个刽子手游戏。程序随机选择10个单词中的一个，仅显示“_”，每次猜测后屏幕都会刷新。

问题是有时循环显示整个屏幕的2倍。所以，我尝试使用 -

cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');

然后Visual告诉我程序触发了一个断点。有什么问题？

#include <iostream>
#include <string>
#include <cstdlib>
#include <ctime>

using namespace std;

void showLogo();
int main()
{
    int number, amount;
    int mistake = 5;
    int wrongLetter = 0;
    char letter;
    char tab[13];
    char unknown[13];
    char usedLetters[5];
    char *wsk;

    srand(time(NULL));
    number = rand() % 10;  //choose one of 10 words

    string words[10] ={"LONGITUDINAL","UNFORTUNATELY","EXPLANATORY",
                       "PERENNIAL","UNPUTDOWNABLE","REMORSELESS",
                       "INTERMITTENT","ADJUDICATE","INERSTITIAL",
                       "MALPOSED" };

    amount = size(words[number]);  
    strcpy_s(tab, words[number].c_str()); //string to char

    for (int i = 0; i < amount; i++)
    {
        unknown[i] = '_';
    }

    while (mistake)
    {
        int noOfGuessed = 0;
        showLogo();

        cout << "You have: " << mistake << " chances." << endl << endl;
        cout << "Used words: ";
        for (int i = 0; i < wrongLetter; i++)
        {
            cout << usedLetters[i] << " ";
        }
        cout << endl << endl;

        for (int i = 0; i < amount; i++)
        {   
            cout << unknown[i] << "  ";
        }
        cout << "\t Enter a letter: ";

        letter = getchar();
        letter = toupper(letter);

        for (int i = 0; i < amount; i++)
        {
            if (letter == tab[i] && unknown[i] == '_')
            {
                wsk = &unknown[i];
                *wsk = letter;
                noOfGuessed++;
            }
        }

        if (noOfGuessed == 0)
        {
            mistake--;
            usedLetters[wrongLetter] = letter;
            wrongLetter++;
        }

        cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
        system("cls");
    }

    system("pause");    
    return 0;
}

void showLogo()
{
    cout << "\t\t\t\t\t\t\t HANGMAN" << endl;
    cout << endl;
    cout << endl;
    cout << endl;
}

Answer 1

ignore()将设置cin的eof位，并使流处于错误状态。调用ignore()后，应始终清除流错误位。

cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
cin.clear();

Visual触发了一个断点c ++

1 个答案: