Question

我正在尝试更新列NOTIFIED，因为我循环遍历此表中名为notifyTable的行

if coinMarketValue > value and notified == 0:

这是我目前的代码

connection = sqlite3.connect('notify.db')

c = connection.cursor()    
c.execute('SELECT * FROM notifyTable')
data = c.fetchall()


for row in data:
    authorID = row[1]
    coin = row[2]
    operator = row[3]
    value = row[4]
    coinMarketValue = row[5]
    notified = row[6]

    if operator == '<':           
        if coinMarketValue < value and notified == 0: #notified hasnt been set true 
            print("coin market value is less than value so updating notifed to True")             
            connection.execute("UPDATE notifyTable set notified = 'True' WHERE coinMarketValue < value AND notified == 0")
            connection.commit()

是的，现在代码遍历每一行，如果条件为True。

coinMarketValue < value AND notified == 0

然后它会将所有Notified列更新为True - 而不是仅更新当前行。

那么，我怎样才能更新脚本当前正在处理的行上的Notified（而不是更新所有行）

由于

Answer 1

如果taskname是主键，则可以执行此操作：

for row in data:
    taskname = row[0]
    # ...

    if operator == '<':           
        if coinMarketValue < value and notified == 0: #notified hasnt been set true 
            # ...
            connection.execute("""UPDATE notifyTable 
                                  SET notified = 'True' 
                                  WHERE coinMarketValue < value 
                                  AND notified = 0
                                  AND taskName = ?""",(taskname,))

循环遍历各行并更新SQLite3 Python的那些行

1 个答案: