我创建了一本字典(很大程度上通过反复试验,所以我有点迷失了),如下所示:
{0:' 68651880',993793:' 68656512',29648:' 68671002',325637:' 68656512',282119: ' 68656512',404490:' 68656512',3595:' 68657355',1549:' 68655127',559630:' 68656512&# 39;,3599:' 68657355',3601:' 68657355',435730:' 68656512',241171:' 68656512',4118:& #39; 68657355',439319:' 68656512',403480:' 68656512',349721:' 68656512',40476:' 68660531&#39 ;,337437:' 68656512',20510:' 68671002',4127:' 68657355',505888:' 68656512',459297:&# 39; 68656512',3419:' 68660531',73533:' 68660531',5201:' 68651903',169511:' 68657355' ,450689:' 68656512',22949:' 68671002',26631:' 68671002',16940:' 68671002',9774:&#39 ; 68651903',50735:' 68671002',449073:' 68656512',374322:' 68656512',350263:' 68656512', 2525:' 68655127 ',411195:' 68656512',237630:' 68671002',24639:' 68671002',1417:' 68655127',3649 :' 68657355',404035:' 68656512',409161:' 68656512',330826:' 68656512',3659:' 68657355& #39;,20044:' 68660531',195661:' 68671002',67482:' 68671002',259151:' 68656512',3310: ' 68657355'}
为了帮助您理解,键(第一个值)是以秒为单位的时间量,值(第二个值)是一堆以6开头的作业ID,都是8位数,有时它们会重复自己。
我需要整理数据,这样我才能看到每个作业ID按升序排列的时间。因此,如果作业ID重复,就像其中一些作业ID一样,每个相应的时间(以秒为单位),我想按升序排序该作业ID。
以下是我感兴趣时如何生成数据列表的代码:
#create urlfriendlylist
for item in urlfriendlylist:
fpp = FarmPageParser("http://farmweb/AnimalFarm/" + item + ".html#subjobs")
fpp.reset()
slowjobs = fpp.getFarmTableHTML(4)
fpp.feed(slowjobs)
x = fpp.table
#turn back into jobid
key = item[0:5] + item[6:9]
#create dictionary of CPU time and jobid
for a in x:
try:
CPUtime = a[2]
#use function to convert hh:mm:ss into ssssss
sec_got = get_sec(CPUtime)
#populate dictionary with loop
dic[sec_got] = key
except: pass
print dic
答案 0 :(得分:2)
您可以为此创建另一个dict,如下所示:
dic2 = {}
for key, value in dic.iteritems():
if not value in dic2:
dic2[value] = []
dic2[value].append(key)
for lst in dic2:
lst.sort()
print dic2