Question

我有这个表单字段，如果条件为真，我想要更改。

<input type="email"
  name="UserEmail"
  id="UserEmail"
  class="form-control"
  ng-class="{'invalid-signup': signUpForm.UserEmail.$invalid && signUpForm.UserEmail.$dirty, 'valid-signup': signUpForm.UserEmail.$valid && signUpForm.UserEmail.$dirty}"
  placeholder="Primary contact email."
  ng-required="true"
  ng-maxlength="30"
  ng-minlength="5"
  ng-model="signUpModel.UserEmail"/>
 <div ng-show="signUpForm.UserEmail.$dirty && signUpForm.UserEmail.$invalid">
  <p ng-show="signUpForm.UserEmail.$error.required">Email is required.</p>
  <p ng-show="signUpForm.UserEmail.$error.pattern">Email is not valid.</p>
  <p ng-show="signUpForm.UserEmail.$error.minlength">Email is too short, min 5 characters.</p>
  <p ng-show="signUpForm.UserEmail.$error.maxlength">Email is too long, max 30 characters.</p>
</div>

所以我有一个标志变量，如果这是真的，我想将字段占位符和值更改为某些内容。

$scope.isGoogleLoginWorking = true;

有没有办法做到这一点。

感谢您的建议。

Answer 1

您可以使用三元运算符

<input type="email"
  name="UserEmail"
  id="UserEmail"
  class="form-control"
  ng-class="{'invalid-signup': signUpForm.UserEmail.$invalid && signUpForm.UserEmail.$dirty, 'valid-signup': signUpForm.UserEmail.$valid && signUpForm.UserEmail.$dirty}"
  placeholder="{{isGoogleLoginWorking?'Primary contact email.':'Something else'}}"
  ng-required="true"
  ng-maxlength="30"
  ng-minlength="5"
  ng-model="signUpModel.UserEmail" ng-value="isGoogleLoginWorking?signUpModel.UserEmail:'Something else'"/>

表单字段/占位符和值

1 个答案: