我有一个JSON数组,格式如下,在PHP中使用foreach循环生成,从WP ACF组生成一个数组(见下文)。在获取此ACF组的特定字段时,我似乎无法使用GROUP BY,因此显示了名称的双重条目(具有不同的时间)。
[
{"name":"Location1","gigs":
{"start":"16:30","end":"21:15","title":"TestTitle1","class":"fri"}
},
{"name":"Location 2","gigs":
{"start":"15:00","end":"19:00","title":"TestTitle2","class":"fri"}
},
{"name":"Location 1","gigs":
{"start":"21:00","end":"22:00","title":"TestTitle3","class":"fri"}
}
]
理想情况下,此JSON数组的格式应如下所示,区别在于具有相同名称/位置的条目应组合如下所示。
[
{
"name":"Location1",
"gigs": [
{"start":"16:30","end":"21:15","title":"TestTitle1","class":"fri"},
{"start":"21:00","end":"22:00","title":"TestTitle3","class":"fri"}
]
},
{
"name":"Location 2",
"gigs": [
{"start":"15:00","end":"19:00","title":"TestTitle2","class":"fri"}
]
}
]
我已尝试过PHP中可用的多个数组合并/合并/排序/等功能,但无法按预期输出。
这是生成数组/ JSON输出的代码:
function get_shows( WP_REST_Request $request ) {
$parameters = $request->get_params();
switch($parameters[1]) {
case 'fri':
$show_day = 'fri';
$show_select_day = '20170901';
break;
case 'sat':
$show_day = 'sat';
$show_select_day = '20170902';
break;
case 'sun':
$show_day = 'sun';
$show_select_day = '20170903';
break;
}
$showDates = array();
$args = array(
'posts_per_page' => -1,
'post_type' => 'performances',
'meta_key' => 'per_date',
'meta_value' => $show_select_day
);
$shows = get_posts( $args );
if ( ! empty( $shows ) ) {
$i = 0;
foreach( $shows as $show ) {
$acf = get_fields($show->ID);
$show_loc = get_the_title(get_field('per_location',$show->ID));
$show_title = get_the_title(get_field('per_busker',$show->ID));
if ( ! empty( $acf ) ) {
$showDates[$i]['name'] = $show_loc;
$showDates[$i]['gigs']['start'] = date("H:i", strtotime($acf['per_time_start']));
$showDates[$i]['gigs']['end'] = date("H:i", strtotime($acf['per_time_end']));
$showDates[$i]['gigs']['title'] = $show_title;
$showDates[$i]['gigs']['class'] = $show_day;
}
$i++;
}
}
return $showDates;
}
任何以正确格式获得输出的建议都非常受欢迎。非常感谢!
答案 0 :(得分:0)
尝试以下解决方案。我已将您的密钥import sqlContext.implicits._
DF1.alias("a").join(DF2.alias("b"),DF1("primary_col") === DF2("primary_col"), "inner").select($"a.col1".alias("first"),$"a.col2".alias("second"),$"b.col4".alias("third"))
更改为import sqlContext.implicits._
DF1.alias("a").join(DF2.alias("b"),DF1("primary_col") === DF2("primary_col"), "inner").select($"a.col1", $"a.col2", $"b.col4".alias("third"))
,因为Location1
Location 1